A or c I’m pretty sure it’s c though hope it helps:)
<h2>
Answer: faster </h2>
The speed of sound varies depending on the medium through which the sound waves travel. In addition, it varies with changes in the temperature of the medium. This is because an <u>increase in temperature means that the frequency of interactions between the particles that transport the vibration increases</u>, hence this increase in activity increases the speed. That is why the speed of sound in a gas is not constant, but depends on the temperature.
So, if we want <u>the speed of sound in a gas to increase</u>, the<u> temperature</u> of that gas must <u>increase</u>, as well.
For example, the higher the air temperature, the greater the velocity of propagation. Experiments have shown that the speed of sound in air increases for every increase in temperature.
Therefore:
<h2>The speed of sound will be faster than in December</h2>
Answer:
0,33 Volt
Explanation:
v = 340 000 m/s - Initial electron speed
m = 9.1·10⁻³¹ kg - Mass of an electron
W = m·v² / 2 - Initial kinetic energy of an electron
W = 9.1·10⁻³¹·(340 000)² /2 ≈ 5.26 · 10⁻²⁰ J (1)
Q = 1.6·10⁻¹⁹ C - Electron charge modulus
The work of the electric field:
A = Q·V (2)
Equate (2) and (1):
Q·V = W
V - Electric field potential difference
V = W / Q = 5.26 · 10⁻²⁰ / 1.6·10⁻¹⁹ ≈ 0,33 Volt
Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
Substitute known values into this equation.
Multiply and simplify.
Divide both sides of the equation by -4.9.
Square root both sides of the equation.
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
Divide both sides of the equation by 3.194382825.
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
Answer:
19.1 deg
Explanation:
v = speed of the proton = 8 x 10⁶ m/s
B = magnitude of the magnetic field = 1.72 T
q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C
F = magnitude of magnetic force on the proton = 7.20 x 10⁻¹³ N
θ = Angle between proton's velocity and magnetic field
magnitude of magnetic force on the proton is given as
F = q v B Sinθ
7.20 x 10⁻¹³ = (1.6 x 10⁻¹⁹) (8 x 10⁶) (1.72) Sinθ
Sinθ = 0.327
θ = 19.1 deg