In the water cycle diagram above, which letter represents

ser-zykov [4K]

Molecules join together releasing photons, which realest heat and light. They do this until they work their way out of the sun

5 0

2 years ago

Read 2 more answers

A student is given 1.525 g of pure CuO. To recover the Cu present in the compound, the dark powdery solid was dissolved in 15.0

ikadub [295]

Answer:

The amount of Mg was enough

Explanation:

In this case, we have to start with the reaction between $Mg$ and $CuO$ , so:

$CuO~+~Mg~->~MgO~+~Cu$

If we check the reaction is already balanced. Now, we can do some stoichiometry to calculate the amount of Mg. The first step is the number of moles of $CuO$ . To this we have to calculate the molar mass of $CuO$ first, so:

Cu: 63.55 g/mol and O: 16 g/mol. So, (63.55+16)= 79.55 g/mol.

Now, we can calculate the moles:

$1.525~g~CuO\frac{1~mol~CuO}{79.55~g~CuO}=0.0192~mol~CuO$

The molar ratio between $Mg$ and $CuO$ is 1:1, so:

$0.0192~mol~CuO=0.0192~mol~Mg$ .

Now we can calculate the mass of Mg if we know the atomic mass of Mg (24.305 g/mol). So:

$0.0192~mol~Mg\frac{24.305~g~Mg}{1~mol~Mg}=0.466~g~Mg$

With this in mind, the student added enough Mg to recover all the Cu.

Note: The HCl doesn't take a role in the reaction. The function of HCl is to dissolve the $CuO$ .

I hope it helps!

3 0

2 years ago

Why doesn't potassium fluoride conduct electricity as a solid?

Korvikt [17]

potassium flouride is an ionic compound and ionic compounds do not conduct electricity in solid form instead it conducts electricity in molten state.Ionic compounds do not conduct electricity in solid state because their ions are fixed while in molten form the ions are free

5 0

2 years ago

What is the change in the freezing point of water when 35.0 g of sucrose is

frez [133]

From the calculations, we can see that, the change in the freezing point is -0.634°C.

<h3>What is freezing point?</h3>

The term freezing point refers to the temperature at which a liquid is changed to solid.

Given that;

ΔT = K m i

Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles

molality = 0.1 moles/ 300.0 * 10^-3 Kg

= 0.33 m

Thus;

ΔT = -1.86°C/mol * 0.33 m * 1

= -0.634°C

Learn more about freezing point:brainly.com/question/3121416

#SPJ1

3 0

1 year ago

Ammonium dihydrogen phosphate, formed from the reaction of phosphoric acid with ammonia, is used as a crop fertilizer as well as

Tema [17]

Answer:

a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.

b) 14.78 grams ammonia is incorporated into 100. g of compound.

Explanation:

a) Ammonium dihydrogen phosphate that is $NH_6PO_4$ .

Molecular mass of ammonium dihydrogen phosphate = M

M = 115 g/mol

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

Percentage of nitrogen:

$\frac{1\times 28 g/mol}{115 g/mol}\times 100=24.34\%$

Percentage of phosphorus:

$\frac{1\times 31g/mol}{115 g/mol}\times 100=26.95\%$

b) Percentage of ammonia in 1 molecule of ammonium dihydrogen phosphate.

Molar mass of ammonia = 17 g/mol

$\%=\frac{17 g/mol}{115 g/mol}\times 100=14.78\%$

Amount of ammonia in 100 grams of compound:

14.78% of 100 g of ammonium dihydrogen phosphate:

$\frac{14.78}{100}\times 100 g=14.78 g$

14.78 grams ammonia is incorporated into 100. g of compound.

4 0

3 years ago