Answer:
Explanation:
Sodium:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Iron:
Fe₂₆= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
Bromine:
Br₃₅ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵
Barium:
Ba₅₆ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s²
Cobalt:
Co₂₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷
Silver:
Ag₄₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹ 4d¹⁰
Tellurium:
Te₅₂= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁴
Radium:
Ra₈₈ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 7s²
Answer:
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Explanation:
First of all, we out down the skeleton equation;
Al + MnO4- → MnO2 + Al(OH)4-
Secondly, we write the oxidation and reduction equation in basic medium;
Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-
Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-
Thirdly, we add the two half reactions together to obtain:
Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-
Lastly, cancel out species that occur on both sides of the reaction equation;
Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O
The simplified equation now becomes;
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Answer:
100 ml = 0.1 L
I divided 100 by 1000 because 1000ml = 1L
The epicardium (external layer), the myocardium (middle layer) and the endocardium (inner layer).
The correct question is: How many moles are in 
atoms of boron.
Answer: There are 145 moles present in atoms of boron.
Explanation:
According to the mole concept, there are 
atoms present in one mole of every substance.
Hence, number of moles present in atoms is calculated as follows.
Thus, we can conclude that there are 145 moles present in atoms of boron.
