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4 years ago

Compared to yellow light, orange light has

Physics

2 answers:

pychu [463]4 years ago

5 0

C. a longer wavelength; if you look at the electro magnetic spectrum of light you will see why

AnnZ [28]4 years ago

5 0

The correct answer is:

C. a longer wavelength

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Which choice correctly describes what happens during heating?

Masja [62]

Answer:

Option 4

Explanation:

During heating actually heat transfer takes place from a body at higher temperature to a body at lower temperature and the heat transfer takes place until both attain the same temperature

Therefore heat transfer depends on the temperature of the systems

Now while comparing the thermal energies of the systems, if both the systems have same mass then the system which is at higher temperature has greater thermal energy when compared to the system which is at lower temperature

So in this case assuming that both the systems have same mass then the energy will leave the system with greater thermal energy and go into the system with less thermal energy as the system with greater thermal energy in this case will be at higher temperature and we are considering this assumption because thermal energy not only depends on temperature but also depends on mass of the system

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4 years ago

imagine that a new planet is discovered with two moons of equal mass, moon A and moon B. The mass of the new planet is greater t

sdas [7]

The gravitational pull on moon A will be lower since it is further away from the new planet.

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4 years ago

Read 2 more answers

I can’t figure this out!!! Answer what you can , please.

tigry1 [53]

a/b. The ball has velocity vector at time $t$

$\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)$

where $v_0=16\dfrac{\rm m}{\rm s}$ is the ball's initial speed and $g=9.8\dfrac{\rm m}{\mathrm s^2}$ .

c. At its highest point, the ball has 0 vertical speed. This occurs when

$v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s$

d. Recall that

${v_y}^2-{v_{0y}}^2=-2g\Delta y$

so that at its highest point,

$0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m$

e. This is just twice the time it takes for the ball to reach its maximum height, $t=2.9\,\mathrm s$ .

f. The ball's horizontal position after time $t$ is

$v_0\cos63^\circ\,t$

so that after the time found in part (f), the ball has traveled

$v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m$

4 0

4 years ago

The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current

Komok [63]

Answer:

$I=0.047A$

Explanation:

Let's use Ohm's law:

$V=IR$

$I=\frac{V}{R}$ (1)

Where:

$V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance$

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

$R=\rho*\frac{l}{A}$ (2)

Where:

$R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}$

Keep in mind that the electrical resistivity of the gold is a known constant which is $\rho_g_o_l_d=2.35*10^{-8}$ and the cross sectional area of the conductor is calculated as: