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emmainna [20.7K]
4 years ago
6

What properties of radio waves makes them suitable for sending signals in mountainous regions?

Physics
1 answer:
marusya05 [52]4 years ago
3 0

one of the property of radio waves is that they have long wavelength. due to their long wavelength , they undergo diffraction around the mountains and thus the waves spread around the mountain. this makes them eligible to be used for  long distance communication. they can coded and decoded also . that is why they are used in television and radio system

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A point source of light is submerged 3.3 m below the surface of a lake and emits rays in all directions. On the surface of the l
krok68 [10]

Answer:

Maximum Radius = 2.89m

Explanation:

The maximum radius will be determined by the angle of incidence which is equal to the critical angle. Now, any angle larger than that will make the light to be totally internally reflected. Hence, we can figure out that angle from Snell’s law where the refracted angle is 90°, and then use the tangent function.

From Snell's law;

n_air*sin90° = n_water*sin(θ _c)

Where;

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Refractive index of water; n_water = 1.333

Refractive index of air;n_air = 1

Thus;

1*1 = 1.33sinθ_c

sinθ_c = 1/1.33

θ_c = sin^(-1)0.7519

θ_c = 48.76°

Like I said earlier, we'll use tangent to find the radius.

Thus;

tanθ_c = d/R

From the question, d = 3.3m

Thus;

3.3/tan48.76 = R

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8 0
4 years ago
Beaker contain 200 mL of water what is volume of water in cm cube and m cube
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<u><em>Part 1:</em></u>

<u>The basics of conversions state that:</u>

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This means that the ratio between them is 1:1

Therefore, 200 ml of water would be equivalent to 200 cm³ of water

<u><em>Part 2:</em></u>

<u>Again, the basics of conversion states that:</u>

1 ml is equivalent to 1 * 10⁻⁶ m³

We will use cross multiplication to convert 200 ml to m³ as follows:

1 ml ................> 1 * 10⁻⁶ m³

200 ml .........> ??

200 ml = \frac{200*1*10^{-6}}{1}  = 0.0002 m³

Hope this helps :)

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Answer:

See answer below

Explanation:

Hi there,

I'm a bit late with this response, but I attached the work below.

Good luck with physics, have fun!

thanks,

4 0
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