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3 years ago

How many milliliters of 5.0M K2Cr2O7 solution must be diluted to prepare 250.0 mL of 0.37 M solution

Chemistry

1 answer:

creativ13 [48]3 years ago

3 0

Hi, I am an AP chemistry student so I am confident this answer is correct. The answer would be 3.38 L or 3380 mL

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An object with a mass of 7.1 g raises the level of water in a graduated cylinder from 25.1 mL to 32.4 mL. What is the density of

jeka57 [31]

Answer:

0.9726g/ml

0.9726g/cm³

Explanation:

Density is found by dividing mass by volume.

Density = mass/volume

mass = 7.1g

volume= the new level of water raised - the initial level of water

volume = 32.4 - 25.1

volume = 7.3 ml

Volume is the amount of space occupied by an object.meaning the amount of volume displaced by the object is its volume.

density = 7.1 /7.3

density = 0.9726g/ml

or 0.9726 g/cm³

If you need any clarification or more explanation pls do mention at the comment section.

hope this helps and if it does pls mark as branliest answer thx

5 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0

3 years ago

Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a

djverab [1.8K]

solution:

the change in the boiling point is given as,

dTbp =2.30°c

elevation constant for the solvent is given by,

kb=0.512°c/m

$molality=\frac{dTBP}{KB\times m}\\=\frac{2.30}{0.512c/m}$

= 4.49m

8 0

3 years ago

How many bonds does CIO3- have, the chlorate ion have?

chubhunter [2.5K]

2 ions in that solution.

7 0

3 years ago

What are Seismic waves?

Vikki [24]

Answer:

Seismic waves are waves of energy that travel through Earth's layers, and are a result of earthquakes, volcanic eruptions, magma movement, large landslides and large man-made explosions that give out low-frequency acoustic energy

Explanation:

hope this helps if so please brainliest

Merry Christmas

6 0

3 years ago