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3 years ago

How many milliliters of 5.0M K2Cr2O7 solution must be diluted to prepare 250.0 mL of 0.37 M solution

Chemistry

1 answer:

creativ13 [48]3 years ago

3 0

Hi, I am an AP chemistry student so I am confident this answer is correct. The answer would be 3.38 L or 3380 mL

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Consider the following reaction 2 N2O(g) => 2 N2(g) + O2(g) rate = k[N2O]. For an initial concentration of N2O of 0.50 M, cal

den301095 [7]

Answer:

After 2.0 minutes the concentration of N2O is 0.3325 M

Explanation:

Step 1: Data given

rate = k[N2O]

initial concentration of N2O of 0.50 M

k = 3.4 * 10^-3/s

Step 2: The balanced equation

2N2O(g) → 2 N2(g) + O2(g)

Step 3: Calculate the concentration of N2O after 2.0 minutes

We use the rate law to derive a time dependent equation.

-d[N2O]/dt = k[N2O]

ln[N2O] = -kt + ln[N2O]i

⇒ with k = 3.4 *10^-3 /s

⇒ with t = 2.0 minutes = 120s

⇒ with [N2O]i = initial conc of N2O = 0.50 M

ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)

ln[N2O] = -1.101

e^(ln[N2O]) = e^(-1.1011)

[N2O} = 0.3325 M

After 2.0 minutes the concentration of N2O is 0.3325 M

3 0

3 years ago

The farming methods promoted by the California Ricelands Habitat Partnership are best described as beneficial to both farmers an

kiruha [24]

Answer:The farming methods promoted by the California Ricelands Habitat Partnership are best described as beneficial to both farmers and wetland species because California Rice Commission and individual growers to further enhance the habitat [ value of California’s rice fields to waterbirds. This collective approach creates synergy for fully realizing the wildlife values in California rice

6 0

3 years ago

2. Calculate the number-average molecular weight of a random poly (isobutylene-isoprene) copolymer in which the fraction of isob

Phoenix [80]

Answer : The number-average molecular weight is, 97500 g/mol

Explanation :

First we have to calculate the molecular weight of isobutylene and isoprene.

The molecular formula of isobutylene and isoprene is, $C_4H_8$ and $C_5H_8$

Molecular weight of $C_4H_8$ = 4(12 g//mol) + 8(1 g/mol) = 56 g/mol

Molecular weight of $C_5H_8$ = 5(12 g//mol) + 8(1 g/mol) = 68 g/mol

Now we have to calculate the average repeat molecular weight.

Average repeat molecular weight = $0.25\times (56g/mol)+(1-0.25)\times (68g/mol)$

Average repeat molecular weight = 65 g/mol

Now we have to calculate the number-average molecular weight.

Number-average molecular weight = Average repeat molecular weight × Degree of polymerization

Number-average molecular weight = (65 g/mol) × (1500)

Number-average molecular weight = 97500 g/mol

Thus, the number-average molecular weight is, 97500 g/mol

5 0

3 years ago

Which elements do hydrogen fuel cells combine to produce electricity?<br> (9TH GRADE SCIENCE)

Andrej [43]

<span>it will convert the energy produced by a chemical reaction into usable electric power.</span>

5 0

3 years ago

Determine the total volume of a balloon if it is inflated with 2.50g helium at 180C and 0.87atm.

puteri [66]

Answer:

V = 267.2 L

Explanation:

Given data:

Volume of balloon = ?

Mass of helium = 2.50 g

Temperature of gas = 180°C

Pressure = 0.87 atm

Solution:

Number of moles of helium:

Number of moles = mass/molar mass

Number of moles = 2.50 g/ 4 g/mol

Number of moles = 0.625 g

Volume of helium:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

0.87 atm× V = 0.625 mol × 0.0821 atm.L/mol.K×453 K

V = 232.45 atm.L /0.87 atm

V = 267.2 L

5 0

2 years ago