Answer:
Explanation:
in a combustion of ethane 2 moles of ethane react with 7 moles of O2
now no of moles in 54 gram of O2=mass/ molar mass
moles =54/32=1.7 moles
if 7 moles of O2 required 2 moles of ethane then 1.7 mole required=?
7 moles of O2=2 moles of C2H6
1.7 moles of O2=1.7*2/7=0.5 moles of C2H6
0.5 moles of C2H6 contain how much grams=?
mass= moles*molar mass=0.5*30=15
It's essentially another word for concentration, of the acid. e.g. "the molarity of the acid is 3moldm^-3"
Answer:
1.61 x 10²⁰ molecules
Explanation:
Given parameters:
Mass of the hydrogen gas = 8.01 x 10⁻⁴g
Unknown
Number of molecules of NH₃ = ?
Solution:
Given reaction:
N₂ + 3H₂ → 2NH₃
We have to solve from the known to the unknown
- The known specie is the mass of H₂ ;
find the number of moles of the specie;
number of moles = 
Molar mass of H₂ = 2(1) = 2g/mol
Number of moles =
= 0.0004mol
- 3 moles of H₂ will produce 2 moles of NH₃
0.0004 moles of H₂ will produce
= 0.00027moles of NH₃
1 mole of a substance contains 6.02 x 10²³ molecules
0.00027mole of NH₃ will contain 0.00027 x 6.02 x 10²³
= 1.61 x 10²⁰ molecules
Answer:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
<u>Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<u>Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<u>Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<em><u>This is all I have for now! Hope this can help! :)</u></em>