The dichotomous key is not given here, however, the correct dichotomous key is as follows:
step- 1a cell has a nucleus and organelles - go to step 2
1b cell has no nucleus or organelles - bacterial cell
step- 2a cell has a cell wall - go to step 3
2b cell has no cell wall - animal cell
step- 3a cell has chloroplasts - plant cell
3b cell has no chloroplasts - fungal cell
Using this dichotomous key the cell can be identified as - Fungal cell.
A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.
Identification of the given cell:
1. Follow step 1.
- If cells have a nucleus and organelles - yes then go to step 2
2. follow step 2.
- 2a. if cell has a cell wall - yes go to step 3
3. follow step 3.
- 3a. if cell has chloroplasts - no then fungal cell
Fungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.
Thus, Using this dichotomous key the cell can be identified as - Fungal cell.
Learn more about fungal cells:
brainly.com/question/14470940
Answer:
H₂CO₃ H₂O ⇄ HCO₃⁻ + H₃O⁺ Ka1
HCO₃⁻ + H₂O ⇄ CO₃⁻² + H₃O⁺ Ka2
CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb1
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻ Kb2
Explanation:
Formula for carbonic acid is: H₂CO₃
It is a dyprotic acid, because it can release two protons. We can also mention that is a weak one. The equilibrums are:
H₂CO₃ H₂O ⇄ HCO₃⁻ + H₃O⁺ Ka1
HCO₃⁻ + H₂O ⇄ CO₃⁻² + H₃O⁺ Ka2
When the conjugate strong bases, carbonate and bicarbonate take a proton from water, the reactions are:
CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb1
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻ Kb2
Notice, that bicarbonate anion can release or take a proton to/from water. This is called amphoteric,
Data:
<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.
Quesiton: Vapor pressure of water
Solution:
Raoult's Law: </span><span><span>The vapour
pressure of a solution of a non-volatile solute is equal to the vapour
pressure of the pure solvent at that temperature multiplied by its mole
fraction.
Formula: p = Xsolvent * P pure solvent
X solvent = moles solvent / moles of solution
molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol
moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol
molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol
moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol
moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol
Xsolvent = 7.50mol / 7.81mol = 0.960
p = 233.7 torr * 0.960 = 224.4 torr
Answer: 224.4 torr
</span> </span>
The substance is lipid substance
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