Question

A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit, the separation distance between adjacent bright fringes on the screen is 0.0290 mm. When instead, 500 nm light is used, what is the separation distance (in mm) between adjacent bright fringes

Answer 1

Answer:

β 2 = 0.02575 mm

Explanation:

given data

wavelength = 563 nm

separation distance between adjacent bright fringes =  0.0290 mm

wavelength = 500 nm

solution

we get here separation distance between adjacent bright fringes that is express as

β = $\frac{\lambda D }{d}$    ..................................1

here D is distance from plane of slit to screen

and d is slit sepation that is constant

so

$\frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}$  

β 2 = $\frac{500}{563} \times 0.0290$  

β 2 = 0.02575 mm