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nexus9112 [7]
3 years ago
11

A closed container is filled with oxygen. the pressure in the container is 405 kpa . what is the pressure in millimeters of merc

ury? express the pressure numerically in millimeters of mercury.
Physics
1 answer:
kari74 [83]3 years ago
8 0

1 mm Hg pressure is the pressure due to 1 mm height of mercury

so it is given as

P = \rho g h

P = 1 * 10^{-3} * 13700 * 9.8 = 134.26 Pa

now we know that pressure is

P = 405 kPa

P = 405 * 10^3 Pa

so in mm Hg this pressure is

P = \frac{405 * 10^3 }{134.26} = 3016.5 mm Hg

so pressure in millimeter Hg will be 3016.5 mm Hg

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Answer:

minimum stopping distance will be d = 75 m

Explanation:

Maximum force exerted by the bracket is given as

F = 9000 N

now we know that mass of the object is

m = 6000 kg

so the maximum acceleration that truck can have is given as

F = ma

9000 = 6000 a

a = 1.5 m/s^2

now for finding minimum stopping distance of the truck

v_f^2 - v_i^2 = 2a d

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4 0
3 years ago
El coeficiente de variación de la resistencia con la temperatura del carbón es -0.0005/°c.Si la resistencia de una resistencia d
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Answer:

 R (120) = 940Ω

Explanation:

The variation in resistance with temperature is linear in metals

           ΔR (T) = R₀ α ΔT

where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC

let's calculate

            ΔR = 1000 (-0,0005) (120-0)

            ΔR = -60 Ω

            ΔR = R (120) + R (0) = -60

            R (120) = -60 + R (0)

            R (120) = -60 + 1000

            R (120) = 940Ω

3 0
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Is 40,000 °C hotter or colder than 3,600 °C????
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Yes because if 0*c equals 32*F than the higher the number the hotter it is
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Which things determine an element's electronegativity? Check all that apply. A. The size of the atom of that element B. Whether
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D. The number of electrons
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A 5 kg bowling ball with a velocity of +10 m/s collides with a stationary 2 kg bowling pin. If the ball's final velocity is +8 m
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Answer:

<h2>The pin's final velocity is 5m/s</h2>

Explanation:

Step one:

given data

mass of ball m1=5kg

initial velocity of ball u1=10m/s

mass of pin m2=2kg

initial velocity of pin u2= 0m/s

final velocity of ball v2=8m/s

final velocity of pin v2=?

Step two:

The expression for elastic collision is given as

m1u1+m2u2=m1v1+m2v2

substituting we have

5*10+2*0=5*8+2*v2

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divide both sides by 2

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