Question

8.98L of gas is collected at 32.8°C. Find the volume the gas will occupy at -19.9°C if the pressure remains constant.​

Answer 1

Answer:

$\boxed{\text{2.47 L}}$

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 2.98 L; T₁ =  32.8 °C

V₂ = ?;         T₂ = -19.9 °C

Calculations:

(a) Convert temperatures to kelvins

T₁  = ( 32.8 + 273.15) K = 305.95 K

T₂ =  (-19.9 + 273.15) K = 253.25 K

(b) Calculate the new volume

$\begin{array}{rcl}\dfrac{V_{1}}{T_{1}} &= &\dfrac{V_{2}}{T_{2}}\\\\\dfrac{2.98}{305.95} &= &\dfrac{V_{2}}{253.25}\\\\9.740 \times 10^{-3} &= &\dfrac{V_{2}}{253.25}\\\\{ V_{2}} &=& 9.740 \times 10^{-3} \times 253.25\\&=& \textbf{2.47 L}\\\end{array}\\\text{The gas will occupy \large \boxed{\textbf{2.47 L}} }$