Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer: 5, 8
<u>Step-by-step explanation:</u>
The difference between 3 times a number and -8 is BETWEEN 23 and 32
Note: "difference" means subtraction --> 3x - (-8) --> 3x + 8
23 < 3x + 8 < 32
15 < 3x < 24 <em> subtracted 8 from all 3 sides</em>
--> 5 < x < 8 <em>divided 3 from all 3 sides</em>
X = 1 hr lessons and y = 1/2 hr lessons
x + y = 35......y = 35 - x
40x + 25y = 1115
40x + 25(35 - x) = 1115
40x + 875 - 25x = 1115
40x - 25x = 1115 - 875
15x = 240
x = 240/15
x = 16 <=== there are 16 one-hr lessons
and 19 half-hr lessons
The largest possible value of b is 10, since for some x = x₀ it could be the case that f(x₀) = -5 and g(x₀) = -2; then f(x₀) g(x₀) = -5 × -2 = 10.
