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3 years ago

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According to Faraday's law, voltage cannot be changed by changing the magnetic field strength.

1 answer:

adell [148]3 years ago

5 0

The statement ‘According to Faraday's law, voltage cannot be changed by changing the magnetic field strength’ is false. No matter how the change is created, voltage will always be produced and it could be the magnetic field strength, moving magnet toward or away from the coil etc. This is because the voltage is directly proportional to the number of turns and the magnetic flux.

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Check the dimensional consistencies of s =vot+1/2at2

Leni [432]

Answer:

s is distance so it's dimensions become L.

Nd other side we have ut+1\2at^2.

as 1\2 is a constant it will have dimensions and apply the dimensions to other quantities.

on solving u will get L there also i,e ur LHS = RHS.

thus the equation is dimensionally consistent.

Explanation:

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3 years ago

An object that is falling has the following type(s) of energy. Ignore air resistance.

Anton [14]

Potential and kinetic

6 0

3 years ago

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What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg â€˘ m/s 4. 2 kg â€˘ m/s 6. 0 kg â€˘ m/s 6. 2 kg â

nevsk [136]

The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

<h3> MOMENTUM:</h3>

Momentum of a substance is the product of its mass and velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:

Momentum = 5kg × 1.2m/s

Momentum = 6kgm/s.

Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

Learn more about momentum at: brainly.com/question/250648?referrer=searchResults

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3 years ago

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A cylindrical container with a cross-sectional area of 66.2 cm2 holds a fluid of density 856 kg/m3 . At the bottom of the contai

Ugo [173]

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a) Let us assume the depth be h

As we know that

$Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h$

After solving this,

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

b)

Given that

height of the extra fluid is

$h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}$

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

$Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000$

Pb' = 122 KPa

3 0

3 years ago

A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.

enot [183]

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

<u>Formula Used here</u>

$\boxed{\bf{\Delta \: V \: = acceleration \: \times time \:}}$

<u>Substituting </u><u>the </u><u>given </u><u>value</u>

<u> $\sf\longrightarrow\Delta\:V \: = 2 \times 4 \\ \\ \\ \sf\longrightarrow\Delta\:V \: =8m {s}^{ - 1}$ </u>

<u>Therefore</u><u>,</u>

<u>Change </u><u>in </u><u>velocity </u><u>is </u><u>8</u><u> </u><u>m/</u><u>s</u>

7 0

2 years ago