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Flura [38]
3 years ago
11

What is the difference between neon and carbon

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
6 0
Carbon is like gas that the different
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The initial concentration of reactant in a first-order reaction is 0.27 M. The rate constant for the reaction is 0.75 s−1. What
e-lub [12.9K]

Answer:

≈ 0.10M

Explanation:

[A]o = 0.27M

Rate constant, k = 0.75 s−1

[A] = ?

time, t = 1.3

Integrated formular for a first order reaction is given as;

ln[A] = ln[A]o − kt

ln[A] = ln(0.27) - 0.75(1.3)

ln[A] = -1.309 - 0.975

ln[A] = -2.284

[A] = 0.1019M ≈ 0.10M

4 0
4 years ago
Read 2 more answers
If the pH of the solution is 10, what is the [OH-] concentration?
swat32

Answer:

1×10^{-4}M

Explanation:

To solve this, you will need to do multiple steps.

Firstly, you will have to convert to pOH from pH, which is done by simply subtracting 14-10 to get a pOH of 4.

Then, use the following formula to calculate the [OH-} concentration:

[OH-]= 10^{-pOH}

When converted to Scientific Notation<u>,</u> you get a resulting answer of

<u>1×</u>10^{-4}M<u>.</u>

5 0
3 years ago
Three carbon atoms are linked by single covalent bonds such that they form the shape of a V. All of the unshared electrons form
Nostrana [21]

Answer:

C) 8

Explanation:

Total number of carbon atoms = 3

Number of single bonds = 3

So, each carbon is bonded to the next carbon with the single bond, Number of unshared electrons left with the terminate carbons are 3 and with the intermediate carbon is 2.

Thus, the two terminate carbon have 3 hydrogen each and the intermediate will have 2.

<u>Total - 8</u>

6 0
3 years ago
In a chemical reaction where do the products appear?
Oksana_A [137]
C. On the left side .. what the chemical uses is always on the left and what it produces is always on the right.
3 0
3 years ago
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What is the mole to mole relationship between copper and zinc? Cu2+(aq)+-&gt;Cu(s)+Zn2+(aq)
Aliun [14]

The reaction is missing the Zn(s) in the reactants. The stoichiometry of the copper/zinc is 1 mole to 1 mole

5 0
4 years ago
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