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torisob [31]
4 years ago
8

Mizar is a star system that is composed of two pairs of stars, mizar A and mizar B, or four stars in total. What do astronomers

call a system that is composed of more than two starts?
Chemistry
2 answers:
algol [13]4 years ago
8 0

Answer:

Multi-star system.

Explanation:

Multi star systems are what scientists call systems of stars that are composed by 3 or more stars, this is more than two stars, most of the multi stars systems have only three stars this is because the logistics and forces necessaries to create a system that has 4 or more stars are really complicated and less likely to occur.

ratelena [41]4 years ago
7 0
Mizar is a quadruple or quaternary star system.
When there is more than two stars, it is called a star system or multiple star system or stellar system.
Depending on the number of stars, they are also called a triple, quadruple or quintuple star system or trinary, ternary, quaternary, quintenary, sextuple, sextenary, septuple or septenary star system.
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Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
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