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sertanlavr [38]
3 years ago
5

100 pointts pls answer quick and no link :In the reaction, Hydrogen + Iodine --> Hydrogen Iodide at equilibrium, some Iodine

is is added. What happens to the equilibrium?
Chemistry
1 answer:
sesenic [268]3 years ago
4 0

Answer:

the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.

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What happens to the amount of energy when it is transferred from potential to kinetic?
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4 years ago
1. A 5.455-g sample of impure CaCl2 is dissolved and treated with excess potassium carbonate solution. The dried CaCO3 (calcium
Helen [10]

Answer:81.6%

Explanation:

Mass of CaCO3=4.010 g

Molar mass of CaCO3= 40+12+(16×3) = 100 g/mol.

Recall: number of moles(n)= mass÷ molar mass.

n=4.010÷100 = 0.0401 mol.

Molar mass of CaCl2 = 40+71= 111 g/mol.

Number of mol of CaCl2 = 5.455÷111= 0.04914 g/mol.

Mass of CaCl2 = 0.0401 × 111 = 4.4511 g of CaCl2.

Percent by mass of CaCl2 = (4.4511÷5.455) × 100

= 0.815967 ×100 = 81.5967%

Approximately; 81.6%.

8 0
4 years ago
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How many grams of ca(no3)2 can be produced by reacting excess hno3 with 6.33 g of ca(oh)2?
xeze [42]

Answer:

Amount of Ca(NO3)2 produced = 14.02 g

Explanation:

The given reaction can be depicted as follows:

Ca(OH)2 + 2HNO3 → Ca(NO3)2 + 2H2O

Since it is given that HNO3 is in excess, the limiting reactant is Ca(OH)2

Now, Mass of Ca(OH)2 = 6.33 g

Molar mass of Ca(OH)2 = 74 g/mol

Moles\ Ca(OH)2 = \frac{Mass}{Molar\ Mass} = \frac{6.33 g}{74 g/mol} =0.0855

Based on the reaction stoichiometry:

1 mole of Ca(OH)2 forms 1 mole of Ca(NO3)2

Therefore, moles of Ca(NO3)2 produced from the moles of Ca(OH)2 reacted = 0.0855 moles

Molar mass of Ca(NO3)2 = 164 g/mol

Mass\ Ca(NO3)2 \ produced = moles*molar\ mass \\= 0.0855\ moles*164\ g/mol = 14.02\  g

6 0
4 years ago
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How many moles of CO2 exert a pressure of 2.34atm at a volume of 25.6L and a temperature of 305k?
Eduardwww [97]

Answer:

2.39 moles

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 2.34 atm

Volume (V) = 25.6 L

Temperature (T) = 305 K

Number of mole (n) =?

NOTE: Gas constant (R) = 0.0821 atm.L/Kmol

The number of mole of CO₂ can be obtained by using the ideal gas equation as shown below:

PV = nRT

2.34 × 25.6 = n × 0.0821 × 305

59.904 = n × 25.0405

Divide both side by 25.0405

n = 59.904 / 25.0405

n = 2.39 moles

Thus, the number of mole of CO₂ is 2.39 moles.

4 0
3 years ago
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