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sertanlavr [38]

3 years ago

5

100 pointts pls answer quick and no link :In the reaction, Hydrogen + Iodine --> Hydrogen Iodide at equilibrium, some Iodine

is is added. What happens to the equilibrium?

1 answer:

sesenic [268]3 years ago

4 0

Answer:

the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.

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A sample of gas occupies a volume of 67.1 mL . As it expands, it does 135.3 J of work on its surroundings at a constant pressure

Semmy [17]

Answer:

$V_2=1.363x10^{-3}m^3=1363mL$

Explanation:

Hello,

In this case, since the work done at constant pressure as in isobaric process is computed by:

$W= P(V_2-V_1)$

Thus, given the pressure, initial volume and work, the final volume is:

$V_2=V_1+\frac{W}{P}$

Whereas the pressure must be expressed in Pa as the work is given in J (Pa*m³):

$P=783Torr*\frac{101325Pa}{760Torr} =104394Pa$

And the volumes in m³:

$V_1=67.1mL*\frac{1m^3}{1x10^6mL} =6.71x10^{-5}m^3$

Thus, the final volume turns out:

$V_2=6.71x10^{-5}m^3+\frac{135.3Pa*m^3}{104394Pa}\\\\V_2=1.363x10^{-3}m^3=1363mL$

Best regards.

3 0

4 years ago

Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have

Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given that:

$Molarity_{NaOH}=5\ M$

$Volume_{NaOH}=?\ L$

$Volume_{HCl}=1\ L$

$Molarity_{HCl}=0.05\ M$

So,

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$0.05\times 1=5\times Volume_{NaOH}$

$Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L$

<u>The volume of NaOH required is - 0.01 L</u>

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-Dominant- [34]

They are all substances

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A chemist needs 2.00 liters of hydrochloric acid. How many pints is this?

77julia77 [94]

Is that supposed to say 200/2.00??

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Answer the four questions to figure out the four digit code

denis-greek [22]

Answer:

question 1 =c

question 2 =a

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