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3 years ago

Write balanced chemical equation for the oxidation of fe2+(aq) by s2o2−6 (aq).

1 answer:

6 0

To write a balanced chemical equation for the given redox reaction, we need to know the half reactions of the substances involved. Redox reaction means oxidation-reduction reaction. Oxidation is when one loses electrons making it more positive while reduction is gaining electrons which makes it more negative. Iron here is being oxidized and will have the half reaction:

Fe2+(aq) ---> Fe3+(aq) + e+

 S2O2−6 is being reduced in the process and will have a half reaction of:

S2O2-6 + 4H+ + 2e- ----> 2H2SO3

Adding the two half reactions would yield to the balanced chemical equation. We do as follows:

2 (Fe2+ ---> Fe3+ + e+)
S2O2-6 + 4H+ + 2e- ----> 2H2SO3
----------------------------------------------------------------
2Fe2+ + S2O2-6 + 4H+ ----> 2Fe3+ + 2H2SO3 ( balanced oxidation - reduction reaction )

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gtnhenbr [62]

Answer:D

Explanation:

7 0

3 years ago

How many moles of hydrogen are needed to completely react with 2 moles of nitrogen

Natali5045456 [20]

Assuming ammonia is the product of this reaction:

N2+3H2--->2NH3

2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2

You would need 6 mol of hydrogen gas to completely react with 2 mol of nitrogen.

5 0

3 years ago

Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu

MAVERICK [17]

Answer : The initial temperature of system 2 is, $19.415^oC$

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

$-q_1=q_2$

$m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)$

The mass remains same.

where,

$C_1$ = heat capacity of system 1 = 19.9 J/mole.K

$C_2$ = heat capacity of system 2 = 28.2 J/mole.K

$T_f$ = final temperature of system = $30^oC=273+30=303K$

$T_1$ = initial temperature of system 1 = $45^oC=273+45=318K$

$T_2$ = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

$-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K$

$T_2=292.415K$

$T_2=292.415-273=19.415^oC$

Therefore, the initial temperature of system 2 is, $19.415^oC$

8 0

4 years ago

Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin

DanielleElmas [232]

Answer:

74.4 ml

Explanation:

C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given 15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0

3 years ago

Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli

SashulF [63]

88.98 %

The Balance Chemical Equation is as follow,

2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂

According to equation,

331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂

So,

870 g of Pb(NO₃)₂ will produce = X g of PbCl₂

Solving for X,

X = (870 g × 278.1 g) ÷ 331.2 g

X = 730.5 g of PbCl₂

Therefore,

Theoretical Yield = 730.5 g

Also as given,

Actual Yield = 650 g

So using following formula for percentage yield,

%age Yield = (Actual Yield / Theoretical Yield) × 100

Putting values,

%age Yield = (650 g / 730.5 g) × 100

%age Yield = 88.98 %

Brianliest please and thank you.

4 0

3 years ago