The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
<h3>What is Empirical Formula ?</h3>
Empirical formula is the simplest whole number ratio of atoms present in given compound.
Element % Atomic mass Relative no. of atoms Simplest whole ratio
C 40.6 12
= 3.3 
H 5.1 1
= 5.1 
O 54.2 16
= 3.3 
The Empirical formula of compound is C₁H₂O₁ or CH₂O
<h3>How to find the Molecular formula of compound ?</h3>
Molecular formula = Empirical formula × n

= 4
Molecular formula = n × Empirical formula
= 4 (C₁H₂O₁)
Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
Learn more about the Empirical Formula here: brainly.com/question/1603500
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Explanation:
ZnCl2 + F2 → ZnF2 + Cl2