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Vilka [71]
3 years ago
7

If a barrel of oil weighs 1.5 kN, calculate the specific weight, density, and specific gravity of the oil. The barrel weighs 110

N
Engineering
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer

given,

oil barrel weight  = 1.5 k N = 1500 N

weight of the barrel = 110 N

Assuming volume of barrel = 0.159 m³

weight of oil = 1500-110

                     = 1390 N

specific\ weight = \dfrac{weight}{volume}

specific\ weight = \dfrac{1390}{0.159}

            = 8742.14 N/m³

mass = \dfrac{weight}{g}

mass = \dfrac{1390}{9.8}

              = 141.84 kg

density = \dfrac{mass}{volume}

density = \dfrac{141.84}{0.159}

                    = 892.05 kg/m³

Specific\ gravity = \dfrac{density\ of\ oil}{density\ of\ water}

Specific\ gravity = \dfrac{892.05}{1000}

                    = 0.892

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STP stands for standard temperature pressure and NTP stands for normal temperature pressure

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3 years ago
An 1800-W toaster, a 1400-W electric frying pan, and a 75-W lamp are plugged into the same outlet in a 15-A, 120-V circuit. The
Mila [183]

Answer:

a) Current drawn by the toaster = 15A

Current drawn by the electric frying pan = 11.67A

Current drawn by the lamp = 0.625A

b) This combination will blow the 15A fuse as the total current requirement for this setup exceeds the 15A rating of the fuse.

Explanation:

a) For parallel connection, there exists, the same voltage and different currents across all the devices.

Voltage cross each of the 3 devices = outlet voltage of 120V

From their respective power rating, current drawn by each device will be calculated.

P = IV

For the toaster, P = 1800 W, V = 120V

I = 1800/120 = 15A

For the electric frying pan, P = 1400 W, V = 120 V

I = 1400/120 = 11.67 A

For the lamp, P = 75 W, V = 120V

I = 75/120 = 0.625 A

b) Total current in a parallel connection setup = Sum total of all the currents.

Total current drawn by all 3 devices = 15 + 11.67 + 0.625 = 27.295A = 27.3 A

This total current requirement surpasses the 15A current rating of the fuse, therefore, this combination will blow the fuse.

Hope this Helps!!!

6 0
3 years ago
A 50-kN hydraulic press performs pressing and clamping actions. The clamping cylinder force is 4 kN. The pressing cylinder strok
galben [10]

Answer:

The attached figure shows the hydraulic circuit using one sequence valve to control two simultaneous operations performed in proper sequence in one direction only. In the other direction, both the operations are simultaneous.

When we keep the 4/2 DCV in crossed arrow position, oil under pressure is supplied to the inlet port of the sequence valve. It directly flows to Head end port-1. Hence Cylinder 'C1' extends first.

By the end of the extension of cylinder 'C1', pressure in the line increases and hence poppet of sequence valve is lifted off from its seat and allows oil to flow to port-2 and hence, Cylinder 'C2 extends completing the pressing operation.

In the straight-arrow position of 4/2 DCV the oil under pressure reaches the rod end of both the cylinders C1 and C2 simultaneously through port-3. This causes both the cylinders to retract simultaneously.

Also, a Flow control valve is provided tho control the velocity of clamping

Explanation:

find attached the figure

4 0
3 years ago
A cyclone is operated in a closed circuit with a ball mill. The cyclone is feed from a rod mill with a slurry that has a density
pav-90 [236]
Here is the flow sheet. Hope this helps have a great day!!

3 0
3 years ago
Air is saturated with water vapor at 35.0 oC and a total pressure of 1.50 atmospheres. If the molar flow rate of the dry air in
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Answer:

11.541 mol/min

Explanation:

temperature = 35°C

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note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )

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= 5.6291 / 151.95

= 0.03704

calculate the mole fraction of air ( Yair )

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Now to determine the molar flow rate of water vapor in the stream

lets assume N = Total molar flow rate

NH_{2}o = molar flow rate of water

Nair = molar  flow rate of air = 300 moles /min

note : Yair * n = Nair

therefore n = 300 / 0.9629 = 311.541  moles /min

Molar flowrate of water

=  n -  Nair

= 311.541 - 300 = 11.541 mol/min

4 0
3 years ago
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