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Makovka662 [10]
3 years ago
9

Assuming there are no accidents or delays, the distance that a car travels down the interstate

Physics
1 answer:
Ganezh [65]3 years ago
7 0

Explanation:

The distance that a car travels down the interstate  can be calculated with the following formula:

Distance = Speed x Time

(A) Speed of the car, v = 70 miles per hour = 31.29 m/s

Time, d = 6 hours = 21600 s

Distance = Speed x Time

D = 31.29 m/s × 21600 s

D = 675864 meters

or

D=6.75\times 10^5\ m

(b) Time, d = 10 hours = 36000 s

Distance = Speed x Time

D = 31.29 m/s × 36000 s

D = 1126440 meters

or

D=1.12\times 10^6\ m

(c) Time, d = 15 hours = 54000 s

Distance = Speed x Time

D = 31.29 m/s × 54000 s

D = 1689660 meters

or

D=1.68\times 10^6\ m

Hence, this is the required solution.

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I think it is why is Alice suddenly so thirsty

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(d) option is right answer
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Two masses of size m and 4m are connected by a massless thread and are strung over a frictionless pulley of radius R and moment-
tekilochka [14]

Answer:

Total kinetic energy of entire system is 3 mgl

Explanation:

Given two masses: m and 4m.

Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.

Total kinetic energy of entire system = decrease in gravitational potential energy of the system.

Therefore, we have :

ΔKE = Δp

ΔKE = 4mgl - mgl

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Total kinetic energy of entire system is 3 mgl

6 0
3 years ago
N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches the bottom s
Hitman42 [59]

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \frac{ M x_1 -m_{table} x_3}{ x_2}

let's calculate

             m_{maximum} = \frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

5 0
3 years ago
A car travelling on a straight road initially at 45 km/h accelerates for 5.0 s at a constant acceleration of 8.0 m/s2. What is t
lara31 [8.8K]

Answer:

52.5m/s

Explanation:

u=45km/hr=45×1000/60×60=12.5

t= 5 sec

a=8m/s^2

v=?

Now,

v=u+at

v=12.5+8×5

v=52.5

5 0
4 years ago
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