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Makovka662 [10]
3 years ago
9

Assuming there are no accidents or delays, the distance that a car travels down the interstate

Physics
1 answer:
Ganezh [65]3 years ago
7 0

Explanation:

The distance that a car travels down the interstate  can be calculated with the following formula:

Distance = Speed x Time

(A) Speed of the car, v = 70 miles per hour = 31.29 m/s

Time, d = 6 hours = 21600 s

Distance = Speed x Time

D = 31.29 m/s × 21600 s

D = 675864 meters

or

D=6.75\times 10^5\ m

(b) Time, d = 10 hours = 36000 s

Distance = Speed x Time

D = 31.29 m/s × 36000 s

D = 1126440 meters

or

D=1.12\times 10^6\ m

(c) Time, d = 15 hours = 54000 s

Distance = Speed x Time

D = 31.29 m/s × 54000 s

D = 1689660 meters

or

D=1.68\times 10^6\ m

Hence, this is the required solution.

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The speed of a wave is 95 m/sec. If the wavelength of the wave is 0.3 meters, what is the frequency of the wave?
Dimas [21]

<u>Answer</u>:

316.67 Hz

<u>Explanation</u>:

Given:

Wave velocity ( v ) = 95 m / sec

wavelength ( λ ) = 0.3 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 95 / 0.3 Hz

= > f = 950 / 3 Hz

= > f = 316.67 Hz

Hence, frequency of sound is 316.67 Hz.

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Explosion in antarctic sea ice levels may cause another ice age. True or False
lisabon 2012 [21]

Answer:

True Explosion in antarctic sea ice levels may cause another ice age.

Explanation:

True

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Some scientists at the University of Chicago said their analysis shows how the rise of Antarctic sea ice in cold climate could cause a cascade of shifts that could lead to turning the global climate towards glacial periods,

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This theory lost its appeal when astronomers discovered quasars and cosmic background radiation.
JulijaS [17]
<span>the Steady State Theory is the answer to this I believe!</span>
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A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe
Alchen [17]
A)
2revs in 0.08s
   so in 1s thats 25revs
therefore thats <u>50π radians</u> in one second

b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
<u>v=47.123ms^-1</u>

c)
f=1/T
f=1/period for one rotation
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Which two particles would be attracted to each other?
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