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3 years ago

What’s the average for1/2,1/3 and1/6

1 answer:

3 0

1/2+1/3+1/6=3/6+2/6+1/6=6/6=1
By putting them all at the same denominator, you can add them all together.
then you have to divide it by 3 for the three.
1/3 is the average.

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Laura created a website to create T-shirts. In the first month she put up her website she had only a single T-shirt order. Each

kiruha [24]

Laura received 144 orders over the first year

Solution:

Given function is:

f(n) = 2n - 1

Where, "n" is the month

In the first month she put up her website she had only a single T-shirt order

f(1) = 2(1) - 1 = 2 - 1

f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

Thus total orders received over first year:

Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Total orders = 144

Thus she received 144 orders over the first year

8 0

2 years ago

Here is a list of the normal monthly precipitation (in inches) for January for 20 different U.S. cities. 4.0, 1.0, 1.5, 1.6, 2.0

shutvik [7]

Answer:

minimum value = 1.0 , the lower quartile = 2.3, the middle value = 3.5.

the upper quartile = 3.95, the maximum value = 7.3.

Step-by-step explanation:

Five Number Summary of any data consists basically of 5 data sets.

1) The minimum Value

2)The first (lower) quartile

3) The middle value (Median)

4) The third (upper) quartile

5)The maximum value

Now, the given data is 4.0, 1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.1, 5.8, 4.1, 7.3

Arrange it in the ascending order,

1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.0, 4.1, 4.1, 5.8, 7.3

Here,

1) The minimum Value is 1.0

2)The first (lower) quartile is 2.3.

3) The middle value (Median) is 3.5.

4) The third (upper) quartile is 3.95.

5)The maximum value is 7.3.

7 0

3 years ago

Consider a tree T storing 100,000 entries. What is the worst-case height of T in the following cases?

Darina [25.2K]

Answer:

Step-by-step explanation:

a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.

b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.

c.) A red-black tree with 100,000 entries is 2 log 100, 000

d.) The worst-case height of T is 100,000.

e.) A binary search tree storing such a set would have a worst-case height of 100,000.

6 0

3 years ago

Use the angle measures and side lengths to classify the triangle. A) right scalene B) acute scalene C) right isosceles D) obtuse

timurjin [86]

A right scalene is the answer

5 0

3 years ago

These triangle are similar find the value of x A. 2 B.6 C.4 D.3

Nezavi [6.7K]

Answer:

Step-by-step explanation:

in similarity the ratio of the similar sides is the same i.e

10/5 =8/x

2x=8

x= 4

7 0

2 years ago