Answer: It will take 3 days for half of a 10 g sample to decay.
Explanation:
Half-life of sample of an isotope X = 3 days
Sample decayed = 
N=
, time = t
![\ln[\frac{5}{10}]=-0.231\times t](https://tex.z-dn.net/?f=%5Cln%5B%5Cfrac%7B5%7D%7B10%7D%5D%3D-0.231%5Ctimes%20t)

t = 3 days
It will take 3 days for half of a 10 g sample to decay.
Answer:
Explanation:
The halogens have seven electrons in their outermost shell. Each halogen atom lacks a single electron to make their octet a complete one. Elements in the halogen group are univalent and also acceptors of electrons. They are all non-metals and oxidizing agents. The oxidizing power of the halogens decreases from top to down the group. This is why the more powerful halogens displaces a less powerful one from simple salts.
Cl₂ + 2KBr → 2KCl + Br₂
Cl₂ + 2KI → 2KCl + I₂
Br₂ + 2KI → 2KBr + I₂
I₂ + 2KCl → No reaction
Im pretty sure its A.) How many protons
Hey there!:
Volume of rainfall = Area X height
Height = 1 in = 0.254 dm
1mile2 = 2.59 X 10⁸ dm²
so 1300 miles² = 3367 *10⁸ dm²
Volume = 0.254 * 3367 * 10⁸ = 855.218 * 10⁸ dm³
Also,
H2SO4 ionizes as :
H2SO4 --> H⁺ + HSO4⁻
Ka1 is very high so it completely dissociates , due to first dissociation [H⁺] = Concentration of H2SO4
HSO4⁻ --> H⁺ + SO₄⁻²
We also consider it as high dissociation :
so each mole of H2SO4 will give 2 moles of H⁺ (proton)
pH = 3.30 = -log[H⁺]
So [H+] = 0.000501 M = 0.000501 moles / L or moles / dm³
Volume = 855.218 * 10⁸dm³
so moles of H+ present in this volume:
= 0.000501 * 855.218 *10⁸ = 4.28* 10⁷moles
So moles of H2SO4 = 4.28 * 10⁷ / 2 = 2.14 * 10⁷ moles
Molecular weight of H2SO4 = 98 g / mol
Mass of H2SO4:
Moles X molecular weight = 98 * 2.14 X 10⁷ grams = 209.72 * 10⁷ grams in kg:
= 2.09 X 10⁶Kg
Hope that helps!
Answer:
Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence. Scientific methodology includes the following: Objective observation: Measurement and data (possibly although not necessarily using mathematics as a tool)
Explanation: