Answer: I'm guessing but I think this is the answer and also what I put in mine sorry if wrong
Explanation: I think it's "B.- Slightly Acidic" srry if it's too late-
Excess reactant : Na
NaCl produced : = 16.497 g
<h3>Further explanation</h3>
Given
Reaction(balanced)
2Na + Cl₂⇒ 2NaCl
20 g Na
10 g Cl₂
Required
Excess reactant
NaCl produced
Solution
mol Na(Ar = 23 g/mol) :
= 20 : 23 = 0.87
mol Cl₂(MW=71 g/mol):
= 10 : 71 g/mol = 0.141
mol : coefficient :
Na = 0.87 : 2 = 0.435
Cl₂ = 0.141 : 1 = 0.141
Limiting reactant : Cl₂(smaller ratio)
Excess reactant : Na
Mol NaCl based on mol Cl₂, so mol NaCl :
= 2/1 x mol Cl₂
= 2/1 x 0.141
= 0.282
Mass NaCl :
= 0.282 x 58.5 g/mol
= 16.497 g
Answer:
2.67g Ni
Explanation:
To convert from moles to mass, use molar mass as a conversion factor.
Nickel has a molar mass of 58.69g/mol.
0.0455mol (
) = 2.67g Ni
Answer: The student should obtain <u>1.103 g of aluminum oxide </u>
Explanation:
- First we write down the equations that represent the aluminum hydroxide precipitation from the reaction between the aluminum nitrate and the sodium hydroxide:
Al(NO3)3 + 3NaOH → 3NaNO3 + Al(OH)3
Now, the equation that represents the decomposition of the hydroxide to aluminum oxide by heating it.
2Al(OH)3 → Al2O3 + 3H2O
- Second, we gather the information what we are going to use in our calculations.
Volumen of Al(NO3)3 = 40mL
Molar concentration of Al(NO3)3 = 0.541M
Molecular Weight Al2O3 = 101.96 g/mol
- Third, we start using the molar concentration of the aluminum nitrate and volume used to find out the total amount of moles that are reacting
then we use the molar coefficients from the equations to discover the amount of Al2O3 moles produced
finally, we use the molecular weight of the Al2O3 to calculate the final mass produced.
Answer:
The correct order of the elements, taking into account their ionic radius from highest to lowest, is:
<em>a) Cl⁻¹ > F⁻¹ > Na⁺¹ > Mg⁺²</em>
<em>b) S⁻² > O⁻² > Li⁺¹ > Be⁺²</em>
<em>c) S⁻² > Cl⁻¹ > K⁺¹ > Na⁺¹</em>
Explanation:
In ions the ionic radius is determined by the amount of electrons an element gains or loses to become an ion. The more negative an ion is, the greater its ionic radius.
As a rule, anions (negative charge) have a larger ionic radius than cations (positive charge), because the loss of electrons means a contraction of the ionic radius, while the gain of electrons means a greater radius.
To determine which ionic radius is greater in anions or cations with the same charge, it must be considered that in the periodic table the ionic radius increases from top to bottom and from right to left.
Learn more:
Ionic radius example brainly.com/question/2279609
