Answer:
0.54 mole
Explanation:
CH3COOH CH3CH2OH CH3COOCH2CH3 H2O
Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol
Change - x - x + x + x
Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)
K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]
x*(1.0+x)/(1.0-x)(1.0-x) = 4.0
x+x²=4*(1-x)²
x+x² = 4(1² - 2x + x²)
x + x² = 4 - 8x + 4x²
4 - 8x + 4x²- x² - x= 0
3x² - 9x + 4 = 0
x=2.5 , x=0.54
2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,
so answer is 0.54 mole.
i would say D, swimming in the ocean
Answer:
pH = 12.544
Explanation:
0.0350M 0.0350M 0.0350M.........equilibrium
∴ pOH = - log [OH-]
∴ pH + pOH = 14
⇒ [OH-] = 0.0350 M
⇒ pOH = - Log (0.0350)
⇒ pOH = 1.456
⇒ pH = 14 - 1.456
⇒ pH = 12.544
Ok boomer..................
Buffer solutions consist of an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffer solutions are used to have better control of the pH of solutions.
An example of a weak acid and its conjugate base is acetic acid (CH3COOH) and sodium acetate (CH3COONa).
