Answer:1.
2. The rate constant (k) for the reaction is
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
k= rate constant
x = order with respect to
y = order with respect to
n = x+y= Total order
1. a) From trial 1: (1)
From trial 2: (2)
Dividing 2 by 1 :
therefore x=1.
b) From trial 2: (3)
From trial 3: (4)
Dividing 4 by 3:
therefore
2. to find rate constant using trial 1:
1s2,2s2.2p6,3s2,3p6,3d4,4s2
Answer:
63.86 mg
Explanation:
Molar mass is the mass of 1 mol of compound / atom.
molar mass of the compound is - 310 g/mol
mass of 1 mol is - 310 g
therefore mass of 2.06 x 10⁻⁴ mol is - 310 g/mol x 2.06 x 10⁻⁴ mol = 0.06386 g
mass of calcium phosphate is - 63.86 mg
Answer : The enthalpy change of dissolution of is -54.0 kJ/mole
Explanation :
where,
q = heat released by the solution
c = specific heat of water =
m = mass of solution = mass of water + mass of = 102.00 + 1.69 = 103.69 g
= change in temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change of dissolution of
where,
= enthalpy change of dissolution = ?
q = heat released = 0.659 kJ
m = mass of = 1.69 g
Molar mass of = 138.55 g/mol
Therefore, the enthalpy change of dissolution of is -54.0 kJ/mole
solution:
The general form of the equation would be A = P x (1/2) ^ (t/h) where A = final amount, P = start amount, t = time (here in days) and h = half-life (has to be same units as t)
a) A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg