A. Distillation. If the mixtures have different boiling points, the liquid with the lower boiling point will distill off first, followed by the other one.
“B. Filtration” is <em>incorrect</em>. Both liquids will pass through the filter paper.
“C. Sedimentation” is <em>incorrect </em>because it works only for a solid suspended in a liquid.
“D. Evaporation” is <em>incorrect</em>. Both liquids will pass into the atmosphere never to be seen again.
Based on the trend from the graph, the reaction time would have been 32.5 seconds.
<h3>What is the trend in the graph?</h3>
A trend is a general pattern which an observation follows based on previous observations and occurrences.
The reaction time is the time it take for a chemical reaction to occur.
Reaction time is also a measure of reaction rate. The shorter the reaction time, the faster the reaction rate and vice versa.
Based on the trend from the graph, the reaction time would have been 32.5 seconds.
In conclusion, reaction time is a measure of reaction rate.
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The number of moles contained in each of the question are a) 3.935 and b) 0.001165 mol.
<h3>What are moles?</h3>
Moles are a quantity or amount of a substance. Denoted by n.
To calculate moles, mass is divided by the molar mass
n = m/M
mass is divided by the molar mass
a) 230 grams of NaCl
n = m/M
molar mass of NaCl is 58.44 g/mol
n = 230 / 58.44 = 3.935 mol
b) 0.210 g of aspirin
n = m/M
molar mass of aspirin is 180.158 g/mol
n = 0.210 / 180.158 = 0.001165 mol
Thus, the moles are a) 3.935 and b) 0.001165 mol.
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Answer:
The Ka is 9.11 *10^-8
Explanation:
<u>Step 1: </u>Data given
Moles of HX = 0.365
Volume of the solution = 835.0 mL = 0.835 L
pH of the solution = 3.70
<u>Step 2:</u> Calculate molarity of HX
Molarity HX = moles HX / volume solution
Molarity HX = 0.365 mol / 0.835 L
Molarity HX = 0.437 M
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<u>Step 3:</u> ICE-chart
[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4
Initial concentration of HX = 0.437 M
Initial concentration of X- and H3O+ = 0M
Since the mole ratio is 1:1; there will react x M
The concentration at the equilibrium is:
[HX] = (0.437 - x)M
[X-] = x M
[H3O+] = 1.995*10^-4 M
Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4
[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M
[X-] = x = 1.995*10^-4 M
<u>Step 4: </u>Calculate Ka
Ka = [X-]*[H3O+] / [HX]
Ka = ((1.995*10^-4)²)/ 0.437
Ka = 9.11 *10^-8
The Ka is 9.11 *10^-8
