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3 years ago

Why is concentrated sulphuric acid is weak acid

Chemistry

1 answer:

frez [133]3 years ago

7 0

Answer:

Sulfuric acid is a strong acid in any state

Explanation:

You may be thinking if the definition that a weak acid produces relatively few ions in aqueous solution,

If you have 100 % sulfuric acid, there is no water, so the definition does not apply.

Commercial sulfuric acid contains about 2 % water. The sulfuric acid in that small amount of water consists of about 99 % HSO₄⁻ and 1 % SO₄²⁻. The acid is almost completely ionized.

Sulfuric acid is a strong acid.

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How many moles are in 25.3 g of a sample of potassium nitrate (KNO3)?

aksik [14]

Answer:

25.3 g of KNO₃ contain 0.25 moles.

Explanation:

Given data:

Number of moles of KNO₃ = ?

Mass of KNO₃ = 25.3 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of KNO₃:

KNO₃ = 39 + 14+ 16×3

KNO₃ = 101 g/mol

Now we will put the values in formula.

Number of moles = 25.3 g/ 101 g/mol

Number of moles = 0.25 mol

Thus, 25.3 g of KNO₃ contain 0.25 moles.

8 0

3 years ago

A same of gas in a rigid container is at 25.0Cand 1.00atm. What is the pressure of the sample when heated to 220.0C

Crazy boy [7]

Answer:

1.654 atm.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and V are constant, and have different values of P and T:

(P₁T₂) = (P₂T₁)

Knowing that:

P₁ = 1.0 atm, T₁ = 25°C + 273 = 298 K,

P₂ = ??? atm, T₂ = 220°C + 273 = 493 K,

Applying in the above equation

(P₁T₂) = (P₂T₁)

∴ P₂ = (P₁T₂)/(T₁) = (1.0 atm)(493 K)/(298 K) = 1.654 atm.

7 0

3 years ago

When rubbing alcohol and water are at room temperature, which one boils first

Ugo [173]

Answer:

rubbing alcohol

6 0

2 years ago

Read 2 more answers

The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catal

tamaranim1 [39]

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

5 0

3 years ago

Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of

Oksanka [162]

Answer:

B: increase.

Explanation:

When we are considering two gases A and B in a container at room temperature .

We have to find the change on rate of reaction when the number of molecules of gases A is doubled

Let [A]=a and [B]=b

A+B $\rightarrow$ product

Rate of reaction

$R_1=k[A][B]=kab$

We know that concentration is increases with increase in number of moles

When the number of molecules of gases A is doubled then concentration of gases A increases.

Therefore ,[A]=2a

Rate of reaction

$R_2=k(2a)(b)=2kab$

$R_2=2R_1$

Hence, the rate of reaction is 2 times the initial rate of reaction.Therefore, the rate of reaction will increase when the number of molecules of gases A is doubled.

Answer: B: increase.

4 0

4 years ago

Why is concentrated sulphuric acid is weak acid​

Why is concentrated sulphuric acid is weak acid