Answer:
Length=5
Width=100
Step-by-step explanation:
area of a rectangle=length x width
500= 5 x 100
500=500
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
Answer:
A.
Step-by-step explanation:
you have to find the discriminant
b²-4ac for each equation
if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots
if discriminant = 0 there is only one solution
if discriminant > 0 two real solutions
for your given problems
A. discriminant =(-2)²-4*2*15 will be negative
Hello!
Space = 5 cm + 10cm + 10cm + 20cm + 22cm + 30cm => space = 15cm + 10cm + 20cm + 22cm + 30cm => space = 25cm + 20cm + 22cm + 30cm => space = 45cm + 22cm + 30cm => space = 67cm + 30cm => space = 97cm²
Good luck! :)
Answer:
A
Step-by-step explanation:
You can subtract normally when the square roots are the same( like in your problem) but the squares stay they same and the numbers on the outside change.
