What is the energy (in ev) of an x-ray photon that has a wavelength of 3.1 nm ?

Sabrina decided to start selling lemonade on her street. The other kids in the neighborhood noticed that Sabrina was making a lo

suter [353]

Answer:

e. Decreased; Increased

Explanation:

The market equilibrium refers to the condition in which the price and the quantity are in equilibrium if the conditions of supply (what the producers offer) and demand (what the consumers buy) don't change.

In this case we have that as the other kids decide to sell more lemonade the amount of lemonade is going to increase (equilibrium quantity) and because of this the price is going to decrease (equilibrium price).

Then when the other kids open theirown lemonade stand, the equilibrium price descreased and the equilibrium quantity increased.

6 0

3 years ago

Use the information to answer the following question.

Nostrana [21]

Answer:

The answer is B. :)

Explanation:

5 0

3 years ago

on aircraft carriers, catapults are used to accelerate jet air craft to flight speeds in a short distance. One such catapult tak

sineoko [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) - (speed at the beginning)

The jet's change in speed = (70 m/s) - (zero) = 70 m/s

So acceleration = (70 m/s) / (2.5 s)

Acceleration = (70 / 2.5) m/s²

Acceleration = 28 m/s²

That's about 2.9 G's . Jet pilots can endure a lot more than that, but maybe the catapult or the hook on the airplane can't. Let's look a little closer:

F = m A (Newton #2)

The force on the airplane = (18,000 kg) x (28 m/s²)

Force on the airplane = 504,000 Newtons

That's about 113,000 pounds ! Maybe the part of the airplane that the catapult pushes on can't handle any more force than that. Or maybe that's the most force the catapult can deliver.

Also, the REACTION force on the catapult is the same 113,000 pounds. Maybe the hooks or the chains or the struts on the catapult can't handle any more force than that.

That's almost 57 tons for gosh sakes ! Maybe the DECK of the carrier can't handle more force than that, and that's why they can't launch the airplane with acceleration of more than 2.9 G's .

8 0

3 years ago

Calculate the strength and direction of the electric field 300 mm to the right of a -200 C electric

Norma-Jean [14]

Answer: -1.91*10^13 v/m

Explanation: