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kherson [118]
3 years ago
13

Let's take a look at something here. I thought the 15 mph for a base runner was kind of slow. I mean, it was a heck of lot faste

r than I could run, but still 15 mph, equates to about 6.7 m/s. We saw earlier that Usain Bolt average speed was 100 m/9.59 s which is 10.4 m/s. I just looked the NCAA men's 100 m dash record this year--10.82 s. Calculate that speed in in mph.
Physics
1 answer:
frozen [14]3 years ago
7 0

Answer:

The speed is 20.70 mph.

Explanation:

Given that,

Speed = 6.7 m/s = 15 mph

1\ m/s = \dfrac{15}{6.7}

1 m/s =2.24\ mph

In 10.4 m/s,

10.4\ m/s=2.24\times10.4\ mph

10.4\ m/s=23.3\ mph

If 100 m record in 10.82 sec

We need to calculate the speed

Using formula of speed

v = \dfrac{d}{t}

Put the value into the formula

v=\dfrac{100}{10.82}

v=9.242\ m/s

v=9.242\times2.24\ mph

v=20.70\ mph

Hence, The speed is 20.70 mph.

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2 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see
siniylev [52]

Answer:

3.88 * 10^(-15) J

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Potential = 2.2 * 10^6 * 0.011

= 2.42 * 10^4 V

The relationship between electric potential and potential energy is:

P. E. = q*V

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6 0
3 years ago
A steady beam of alpha particles (q = + 2e, mass m = 6.68 × 10-27 kg) traveling with constant kinetic energy 22 MeV carries a cu
cluponka [151]

Answer:

Explanation:

q = 2e = 3.2 x 10^-19 C

mass, m = 6.68 x 10^-27 kg

Kinetic energy, K = 22 MeV

Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A

(a) time, t = 2.8 s

Let N be the alpha particles strike the surface.

N x 2e = q

N x 3.2 x 10^-19 = i t

N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8

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(b) Length, L = 16 cm = 0.16 m

Let N be the alpha particles

K = 0.5 x mv²

22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²

v² = 1.054 x 10^15

v = 3.25 x 10^7 m/s

So, N x 2e = i x t

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N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)

N = 4153.85

(c) Us ethe conservation of energy

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K = q x V

22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V

V = 1.17 x 10^7 V

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3 years ago
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