The Coulomb's force acting between two charges is
where
is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.
Using
, we can find the distance between the two charges when the force is F=19.2 N:
Answer:
1 m/s²
Explanation:
From the question,
Using
a = (v-u)/t.................... Equation 1
Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.
Given: v = 15 m/s, u = 5 m/s, t = 10 s
Substitute these values into equation 1
a = (15-5)/10
a = 10/10
a = 1 m/s²
Hence the acceleration of the bicycle is 1 m/s²
No. It has no acceleration, which just means that the forces acting on it are equal and opposite, not that there are no forces exerted on it.
But if you're talking about the resulting Net Force, then yes you can conclude there is no Net Force acting on an object with no acceleration.
Answer:
<h2>2.55 Hz</h2>
Explanation:
The frequency of the wave given it's velocity and wavelength can be found by using the formula
where
c is the velocity of the wave in m/s
is the wavelength in m
From the question
c = 7.9 m/s
= 3.1 m
We have
We have the final answer as
<h3>2.55 Hz</h3>
Hope this helps you
Answer:
t=444.4s
Explanation:
m=1.5*10^7 kg
F=7.5*10^5 N
v=80km/h*(1h/3600s)*(1000m/1km)=22.22m/s
<u>Second Newton's Law:</u>
F=ma
a=F/m=7.5*10^5/(1.5*10^7)=0.05m/s^2
<u>Kinematics equation:</u>
vf=vo+at=at
vo: initial velocity equal zero
t=vf/a=22.22/0.05=444.4s
