A standard sheet of paper measures 8.5 x 11 inches. find the areas of one such

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

So

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

3 years ago

List price is another term for

mixas84 [53]

I think it's cost price I heard it before somewhere Hope I've been any help to you

4 0

3 years ago

Leonardo wrote an equation that has an infinite number of solutions. One of the terms in Leonardo's equation is missing, as show

Tanya [424]

Answer:

The missing term is 3x

Step-by-step explanation:

Given

-(x - 1) + 5 = 2(x + 3) - _

Required

Find _

For proper identification of the parameters, represent _ with Z

So, the equation becomes

-(x - 1) + 5 = 2(x + 3) - Z

Open bracket (start from the left hand side)

-x + 1 + 5 = 2(x + 3) - Z

-x + 1 + 5 = 2x + 6 - Z

Solve like terms

-x + 6 = 2x + 6 - Z

Subtract 6 from both sides

-x + 6 - 6 = 2x + 6 - 6 - Z

-x = 2x - Z

Subtract 2x from both sides

-x - 2x = 2x - 2x - Z

-3x = -Z

Multiply both sides by -1

-3x * -1 = -Z * -1

3x = Z

Reorder

Z = 3x

Hence, the missing term is 3x

4 0

3 years ago

Read 2 more answers

Find the area of a circle with radius, r = 1cm. Give your answer in terms of π .

natulia [17]

Answer:

A = 1cm*pi

Step-by-step explanation:

5 0

2 years ago

90 dollars ratio in 1:2:3

Mnenie [13.5K]

Answer:

3:6:9

Step-by-step explanation:

1/1+2+3 × 90 = 15

2/1+2+3 × 90 = 30

3/1+2+3 × 90 = 45

8 0

2 years ago