<u>Rules to write the electronic configuration
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Electrons complete orbitals in a way to reduce the energy of the atom. Therefore, the electrons in an atom complete the principal energy levels in order of rising energy (the electrons are getting distant from the nucleus). The order of levels filled appearances like the following
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p
One way to recognise this pattern, apparently the simplest, is to refer to the periodic table and remember where each orbital block drops to rationally understand this pattern. Different way is to make a table like the one below and use vertical lines to determine which subshells resemble with each other.
- S block: The S obstruct in the periodic table of components known as gatherings 1 and 2. There is a limit of two electrons that can possess the s orbital.
- P Block: The P square contains group of 13, 14, 15, 16, 17, and 18, except for Helium.
- D Block: The D block elements are found in groups 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12 of the periodic table.
Answer:
Electrons do not follow specific paths, so the area in which an electron is more scientifically accurate is at the orbitals.
Explanation:
As we know in an atom various electrons are present, they are filled in the orbitals in order to decrease the energy of the atom. These electrons inside the orbitals are arranged from smaller to larger. The lowest one is filled first, the order in which energy is filled is like 1s, 2s, 2p,3s3p,4s,3d etc. The electrons that present far away from the nucleus have the highest energy, the electrons present in the first orbital from the nucleus hold less energy.
Answer:
Solution given:
1 mole of KCl
22.4l
1 mole of KCl74.55g
we have
0.14 mole of KCl74.55*0.14=10.347g
74.55g of KCl22.4l
10.347 g of KCl22.4/74.55*10.347=3.11litre
volume of each solution contains 0.14 mol of KCl contain 3.11litre.
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