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3 years ago

15

Fires in forests can sometimes be stopped by cutting down trees to make a gap called a for break. Which part of the fire triangl

e does this remove?

1 answer:

Ber [7]3 years ago

5 0

It removes the fuel for the flame.

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PLEASE HELPPPPP I WILL GIVE BRAINLIEST!!!!!

Hoochie [10]

If 2500 grams of H2SO4 react with excess NH3 according to the illustration, the amount of ammonium sulfate that can be produced would be 3,370.92 grams. If only 3100 grams of ammonium sulfate were produced, the percentage yield would be 91.96%.

<h3>Stoichiometric calculations</h3>

From the equation of the reaction:

2NH3(aq) + H2SO4(aq) → (NH4)2SO4(aq)

The mole ratio of H2SO4 and (NH4)2SO4 is 1:1

Mole of 2500 grams H2SO4 = 2500/98 = 25.51 moles

Equivalent mole of (NH4)2SO4 = 25.51 moles

Mass of 25.51 moles (NH4)2SO4 = 25.51 x 132.14 = 3,370.92 grams

If 3100 g of (NH4)2SO4 were actually produced, the percentage yield would be:

Percent yield = 3100/3370.92 x 100 = 91.96%

More on percent yield can be found here: brainly.com/question/17042787

6 0

1 year ago

7: How many times can a cell divide?

Mashutka [201]

Explanation:

60 times and it matters why they need to in order to divide

4 0

2 years ago

The molar mass of monopotassium phosphate is 136.09 g/mol. How many moles of monopotassium phosphate are needed to make 250.0 ml

WINSTONCH [101]

Answer:

0.0375 moles

Explanation:

Given that:

Molar mass of monopotassium phosphate = 136.09 g/mol

Given that volume = 250.0 mL

Also,

$1\ mL=10^{-3}\ L$

So, Volume = 250 / 1000 L = 0.25 L

Molarity = 0.15 M

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$0.15=\frac{Moles\ of\ solute}{0.25}$

<u>Thus, moles of monopotassium phosphate needed = 0.0375 moles</u>

4 0

2 years ago

If electricity comes from electrons, does morality come from morons?

Dmitrij [34]

No morality come from each individual person.

8 0

2 years ago

Read 2 more answers

You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out

mina [271]

Answer:

The diameter of the oil molecule is $4.4674\times 10^{-8} cm$ .

Explanation:

Mass of the oil drop = $m=9.00\times 10^{-7} kg$

Density of the oil drop = $d=918 kg/m^3$

Volume of the oil drop: v

$d=\frac{m}{v}$

$v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}$

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = $4\pi r^2$

$a=4\times 3.14\times (0.418 m)^2=2.1945 m^2$

Volume of the oil drop = v = Area × thickness

$\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x$

$x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm$

The thickness of the oil drop is $4.4674\times 10^{-8} cm$ and so is the diameter of the molecule.

6 0

2 years ago