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Lesechka [4]
3 years ago
8

A man of mass M stands on a railroad car that is rounding an unbanked turn of radius R at speed v. His center of mass is height

L above the car, and his feet are distance d apart. The man is facing the direction of motion. How much weight is on each of his feet
Physics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

F_1= Mg- \frac{2Mv^2L}{Rd}

and

F_2=\frac{2Mv^2L}{Rd}

Explanation:

distance of Center of mass from his feet = L

Mass of man = M

Radius of turn = R

Speed = v

distance between the feet =d

Centrifugal force = M×v×v/R = F

Moment due to this force = FL

now as per the situation in the question

force on feet = Force on feet 1 + force on feet 2 = F1 + F2 = Mg

Now, balancing the moment we get by taking moment about feet 2

moment about feet 2 ( outward in the turn) = moment due to centrifugal force ( + ve ) + moment due to weight ( -ve ) + moment due to normal on foot 1 ( + ve) = 0

⇒\frac{Mv^2L}{r} -\frac{Mgd}{2}+\frac{F_1 d}{2} = 0\

solving the above equation we get

F_1= Mg- \frac{2Mv^2L}{Rd}

therefore,

F_2=\frac{2Mv^2L}{Rd}

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An electric pump has 2kW power . How much water will it lift every minute if the height is 10 m ?
valkas [14]

Answer:

Given that,

  • Power = 2000 W
  • time = 60 seconds
  • distance= 10m

Power = work done ÷ time

Here, since the movement is vertical, w = mgh

So,

Power = mgh÷t

2000 = (m × 9.8 ×10) ÷ 60

m = (2000 ×60) ÷98

m = 1224.5kg

3 0
3 years ago
Sort the items based on whether they are simple machines or compound machines.
Tom [10]

Answer:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

Explanation:

Simple machine is the simplest device to use mechanical advantages. It has simplest mechanism to multiply the magnitude of force.

So, pair of tongs, seesaw and wheelbarrow are the example of simple machine because their mechanism is simplest.

Compound machine is a device that is made up of more than one simple machine.

so, sewing machine, fishing rod and reel and crane are example of compound machine because these devices shows more than one machine in it.

Thus, classification is as follows:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

3 0
4 years ago
Read 2 more answers
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collisi
ra1l [238]

Explanation:

Momentum = mass × speed

p = (30 kg) (3 m/s)

p = 90 kg m/s

7 0
3 years ago
A train pulls away from a station with a constant acceleration of 0.42 m/s2. A passenger arrives at a point next to the track 6.
Rina8888 [55]

Answer:

2.69 m/s

Explanation:

Hi!

First lets find the position of the train as a function of time as seen by the passenger when he arrives to the train station. For this state, the train is at a position x0 given by:

x0 = (1/2)(0.42m/s^2)*(6.4s)^2 = 8.6016 m

So, the position as a function of time is:

xT(t)=(1/2)(0.42m/s^2)t^2 + x0 = (1/2)(0.42m/s^2)t^2 + 8.6016 m

Now, if the passanger is moving at a constant velocity of V, his position as a fucntion of time is given by:

xP(t)=V*t

In order for the passenger to catch the train

xP(t)=xT(t)

(1/2)(0.42m/s^2)t^2 + 8.6016 m = V*t

To solve this equation for t we make use of the quadratic formula, which has real solutions whenever its determinat is grater than zero:

0≤ b^2-4*a*c = V^2 - 4 * ((1/2)(0.42m/s^2)) * 8.6016 m =V^2 - 7.22534(m/s)^2

This equation give us the minimum velocity the passenger must have in order to catch the train:

V^2 - 7.22534(m/s)^2 = 0

V^2 = 7.22534(m/s)^2

V = 2.6879 m/s

4 0
3 years ago
An archer tests various arrowheads by shooting arrows at a pumpkin that is suspended from a tree branch by a rope, as shown to t
erik [133]

Answer:

Bounce 1 ,  pass 3,   emb2

Explanation:

(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle.  So it is  Bounce1, pass3, emb2.  

6 0
3 years ago
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