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Kamila [148]
3 years ago
8

A bird carrying a fish (5kg) drops it from 107 meters in the air how fast does the fish hit the ground

Physics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s        

Explanation:

Given data,

The mass of the fish, m = 5 kg

The height of the bird from the surface, h = 107 m

Using the III equation of motion,

                          v² = u² + 2gs

                          <em> v = √(u² + 2gs)</em>

Substituting the values,

                           v = √(0² + 2 x 9.8 x 107)  

                              = 45.795 m/s

Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s        

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A 240 cm length of string has a mass of 2.5 g. It is stretched with a tension of 8.0 N between fixed supports. (a) What is the w
kotykmax [81]

Answer:

a.87.6 m/s

b.18.25 Hz

Explanation:

the equation for the wave speed is expressed as

v=\sqrt{\frac{Tl}{m}}\\

where v is the speed,

           T is the tension in Newton

           l is the length

and      m is the mass

Now since

T=8.0N\\m=2.5g=0.0025kg\\l= 240cm=2.40cm\\

by substituting values into the equation, we have

v=\sqrt{\frac{8*2.40}{0.0025} } \\v=87.6m/s\\

b. the expression for the frequency is giving as

Frequency,f=\frac{v}{2l} \\f=\frac{87.6}{2*2.40} \\f=18.25Hz\\.

Note we 2L as the wavelength because we solving for the fundamental frequency as stated in the question.

3 0
3 years ago
At 0°C, frozen water (ice) changes to liquid water. When an ice cube is placed on something that is warmer than it heat will mov
kondaur [170]

Answer:

a common temperature is reached.

Explanation:

The principle of heat transfer is that heat flows from a substance of higher temperature to that of lower temperature until when a common temperature is reached.

For ice on getting in contact with a hot body; it changes to water at 0°c utilising the latent heat of fusion. After ice has been converted to water at 0°c, water starts increasing in temperature till a common temperature is reached.

8 0
3 years ago
An electron enters a region of space containing a uniform 0.0000193-T magnetic field. Its speed is 121 m/s and it enters perpend
Mandarinka [93]

Answer

Given,

Magnetic field, B = 0.0000193 T

speed, v = 121 m/s

mass of electron, m = 9.11 x 10⁻³¹ Kg

charge of electron, q = 1.6 x 10⁻¹⁹ C

radius of the electron path, r = ?

r = \dfrac{mv}{qB}

r = \dfrac{9.31\times 10^{-31}\times 121}{1.6\times 10^{-19}\times 0.0000193}

r = 3.64 x 10⁻⁵ m

We know frequency is inverse of time period

d = v t

2 \pi r = v \times t

t = \dfrac{2 \pi r}{v}

t = \dfrac{2 \pi \times 3.64\times 10^{-5}}{121}

t = 1.889 x 10⁻⁶ s.

now, frequency

f = \dfrac{1}{t}

f = \dfrac{1}{1.889\times 10^{-6}}

f = 529380\ Hz

3 0
3 years ago
PL-1) A spring that hangs vertically is 25 cm long when no weight is attached to its lower end. Steve adds 250 g of mass to the
Anuta_ua [19.1K]

Answer:

20.42 N/m

Explanation:

From hook's law,

F = ke ......................... Equation 1

Where F = Force applied to the spring., k = spring constant, e = extension.

Make k the subject of the equation,

k = F/e ................. Equation 2

Note: The force on the spring is equal to the weight of the mass hung on it.

F = W = mg.

k = mg/e................ Equation 3

Given: m = 250 g = 0.25 kg, e = 37-25 = 12 cm = 0.12 m.

Constant: g = 9.8 m/s²

Substitute into equation 3

k = (0.25×9.8)/0.12

k = 20.42 N/m.

Hence the spring constant = 20.42 N/m

7 0
3 years ago
An incident ray strikes a boundary at a 72.5-degree angle, resulting in an angle of refraction of 39.6 degrees. The index of ref
Finger [1]
Refractive index is the ration of sin i to sin r where i is the incident angle and r is the refraction angle. 
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                                           = 1.542
The refractive index may be given by the ratio of refractive index of medium 2 to refractive index of medium 1. 
Therefore, 1.542 = n/1.0003
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                               ≈ 1.54
Medium 2 is sodium chloride, refractive index of 1.54

 
6 0
3 years ago
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