Explanation:
1.Pick up litter and throw it away in a garbage can.
2.Blow or sweep fertilizer back onto the grass if it gets onto paved areas. ...
3.Mulch or compost grass or yard waste. ...
4.Wash your car or outdoor equipment where it can flow to a gravel or grassed area instead of a street.
5.Don't pour your motor oil down the storm drain.
Answer:
D is the answer
Explanation:
6.45×7.44= 47.98800
Which if we round of we get 48m
Answer:
5730 years
Explanation:
The half life of carbon-14 is 5730 years. If 50% of the carbon-14 remains, then exactly 1 half life has passed.
The half-life equation is:
A = A₀ (½)^(t / T)
where A is the remaining amount,
A₀ is the initial amount,
t is time,
and T is the half life.
In this case, A = ½ A₀ and T = 5730.
½ A₀ = A₀ (½)^(t / 5730)
½ = (½)^(t / 5730)
1 = t / 5730
t = 5730
Answer:
Explanation:
Galileo proved the superiority of the heliocentric theory over the geocentric theory . Heliocentric theory changed the centre of universe from the earth to the sun . According to this theory , the solar system or the universe revolves around the sun .
But the present knowledge of universe considers sun as one of billions of stars present in the universe , with each star behaving as sun with its own solar system . The universe is made of cluster of stars with each cluster having their own centre around with they revolve . These clusters are called galaxy . Sun is a part of cluster called milky way . Sun along with other star of this galaxy revolves around the centre of its galaxy which is a super massive star .
Hence the old heliocentric theory does not fit into the present framework of universe by the scientist.
From the definition of apparent magnitude, we know that:

where:
m = apparent magnitude
F = corresponding flux
We also know that the flux is given by the formula:

where:
L = luminosity
d = distance
Therefore:

Now, let's apply these formulae to the same star (therefore, same luminosity), using apparent magnitude and absolute magnitude (which is defined as the apparent magnitude the star would have if it were at a distance of 10pc):

Now, let's solve for m:

= <span>

</span>
= 13
Hence,
the apparent magnitude of the star would be m = +13