All categories

3 years ago

Which of the following best describes a fission reaction involving lithium? (1 point)

Chemistry

1 answer:

Feliz [49]3 years ago

6 0

Answer:

D. The nucleus of an atom of lithium splits, resulting in smaller fragments and the release of a large amount of energy.

Explanation:

Fission is the splitting of a nucleus, so this is the only option that involves fission.

A is wrong. Li atoms do not bond to form molecules. Instead, the nuclei are immersed in a sea of electrons.

B is wrong. The joining of two nuclei is fusion.

C is wrong. Adding an electron to an atom of lithium is not a nuclear reaction.

You might be interested in

How many moles are in 297 g of NH3?

BigorU [14]

Answer:

1. 17.4 moles.

2. 1.13 moles

3. 315.5 moles

4. 390.6g

5. 1.13x10⁶ moles

6. 14.8 moles

7. 337 moles

8. 2.15x10²⁴ molecules

9. 3.13x10²⁴ atoms

10. 1.38x10²⁴ particles

11. 1517g

12. 455g of CaF₂

Explanation:

We can convert formula units to moles or vice versa using Avogadro's number and moles to grams using molar mass of the substance:

1. Molar mass NH3: 17.031g/mol

297g * (1mol / 17.031g) = 17.4 moles

2. Molar mass MgCO3: 84.3g/mol

95g * (1mol / 84.3g) = 1.13 moles

3. Using Avogadro's number (6.022x10²³ formula units / mol):

1.9x10²⁶FU * (1mol / 6.022x10²³FU) = 315.5 moles

4. Molar mass H2O: 18g/mol

21.7mol * (18g / mol) = 390.6g

5. Using Avogadro's number (6.022x10²³ molecules / mol):

6.78x10²⁹molecules * (1mol / 6.022x10²³FU) = 1.13x10⁶ moles

6. 8.9x10²⁴FU * (1mol / 6.022x10²³FU) = 14.8 moles

7. Using Avogadro's number (6.022x10²³ atoms / mol):

2.03x10²⁶atoms* (1mol / 6.022x10²³FU) = 337 moles

8. 3.569mol * (6.022x10²³ molecules / 1mol) = 2.15x10²⁴ molecules

9. 5.2mol * (6.022x10²³ atoms / 1mol) = 3.13x10²⁴ atoms

10. Molar mass Li₂SO₄: 109.94g/mol:

36g * (1mol / 109.94g) * (6.022x10²³ molecules / 1mol) * (7 particles / 1molecule) = 1.38x10²⁴ particles

<em>Assuming particles are atoms and in 1 molecule of Li₂SO₄ you have 7 atoms.</em>

11. Molar mass Cl₂: 70.9g/mol:

21.4mol * (70.9g / mol) = 1517g

12. Molar mass CaF₂: 78.07g/mol:

3.51x10²⁴FU * (1mol / 6.022x10²³FU) * (78.07g / mol) = 455g of CaF₂

8 0

3 years ago

How many moles are in 7.1x10^21 atoms of iron?

Nitella [24]

Answer:

0.011 moles

Explanation:

There are about 6.02*10^23 atoms in a mole, so in the given sample, there are

$\frac{7.01 \times {10}^{21} }{6.02 \times {10}^{23} }$

which is about 0.011 moles.

8 0

2 years ago

Which of the following is not capable of reacting with molecular oxygen?

fredd [130]

I think letter b were you put the letters so

6 0

3 years ago

A scientist observed a 5-mL sample of an unknown substance. It is a blue liquid with a density of 1.2 g/cm. the substance reacts

LenaWriter [7]

Characteristic properties can be used to describe and identify the substances, while non-characteristic properties, although can be used to describe the substances, cannot be used to identify them.

Temperature, mass, color, shape and volume are examples of non-characteristic properties.

Density, boiling point, melting point, chemical reactivity are examples of characteristic properties.

List of the properties observed by the scientist:
-----------------------------------------------------------------
Property                                     Type of property
----------------------------------------------------------------
Volume: 5 ml                              non-characteristic
----------------------------------------------------------------
Color: blue                                 non-characteristic
----------------------------------------------------------------
State: liquid                                characteristic
------------------------------------------------------------
density: 1.2 g/cm                        characteristic
------------------------------------------------------------
Reaction: reacts with CO2         characteristic
----------------------------------------------------------

5 0

3 years ago

A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.144g of Oxygen.calculate the percentage compos

oksano4ka [1.4K]

Answer:

Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%

<h2>Hope it's Helpful!!✌️</h2>

5 0

2 years ago