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anastassius [24]
3 years ago
11

How many molecules of glucose are in 1,456 grams of glucose?

Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

4.87×10²⁴ molecules

Explanation:

Given data:

Mass of glucose = 1456 g

Number of molecules = ?

Solution:

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 1456 g/ 180.156 g/mol

Number of moles = 8.1 mol

1 mole of glucose contain 6.022×10²³ molecules

8.1 mol × 6.022×10²³ molecules / 1 mol

48.7×10²³ molecules

4.87×10²⁴ molecules

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What is the symbol of a ion with a 22 protons, 34 neutrons, and 18 electrons
Dominik [7]
Well knowing the number of protons, you can find what the element is, which is Ti = titanium. Then to find the charge, simply subtract 22 and 18 which is +3.

Find the mass number by adding 22 and 34 = 56.

56. +3
Ti

22

This would be the correct notation in isotopic form.
3 0
3 years ago
What is molar concept​
andrew11 [14]

Answer:

The molar mass of a substance is defined as the mass in grams of 1 mole of that substance. One mole of isotopically pure carbon-12 has a mass of 12 g. ... That is, the molar mass of a substance is the mass (in grams per mole) of 6.022 × 1023 atoms, molecules, or formula units of that substance.

Explanation:

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3 years ago
Which statements accurately describe mass? Check all that apply.
Alexxandr [17]

Answer:

the second,third and last statement

Explanation:

please like and Mark as brainliest

4 0
3 years ago
Which type of nuclear radiation is being emitted here?
tekilochka [14]

Answer:

b.Beta

Explanation:

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7 0
3 years ago
Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
2 years ago
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