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Fittoniya [83]
3 years ago
8

a 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. find the ve

locity of the tennis ball after the collision.

Physics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

15.0 m/s

Explanation:

When elastic collision occurs, the final velocities, v of the bodies are obtained by

v_1=\frac {(m_1-m_2)u_1}{m_1+m_2}+ \frac {2m_2u_2}{m_1+m_2}

v_2=\frac {(m_2-m_1)u_2}{m_1+m_2}+ \frac {2m_2u_1}{m_1+m_2}

Where u and m denote initial velocities and mass while the subscripts 1 and 2 are for tennis ball and the other ball

Substituting 0.311 for mass of tennis, 0.0570 for mass of the other ball, 30.3 m/s for velocity of tennis ball and -19.2 m/s  

v_1=\frac {(0.311-0.0570)\times 30.3}{0.311+0.0570}+ \frac {2\times 0.0570\times -19.2}{0.311+0.0570}= 20.91359+ -5.94783= 14.96576 m/s\approx 15.0 m/s

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If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

V_e=\sqrt{\dfrac{2GM}{r}}

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

V_e=\sqrt{\dfrac{2GM}{r\times 2}}

V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

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Behavior is a product of both the situation and the person. Which of the following is an example of a situation that might influ
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A Cessna aircraft has a lift off speed of 147 km/h. What minimum constant acceleration does this require if the aircraft is to b
netineya [11]

Answer:

The acceleration is  a =51945 \ km/h^2

Explanation:

From the question we are told that

   The lift up speed is  v  = 147 \  km/h

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Generally from kinematic equation we have that

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Here u is the initial  speed of the aircraft with value 0 m/ s give that the aircraft started from rest

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Explanation:

Hope this helps

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