All categories

2 years ago

A 755 N force is used to push a 15 Kg box across the floor. What is the acceleration of the box?

Physics

2 answers:

Reil [10]2 years ago

6 0

Answer:

a = 151/3 m/s²

General Formulas and Concepts:

Forces

Newton's 2nd Law of Motion: F = ma

F is force (in N)
m is mass (in kg)
a is acceleration (in m/s²)

Explanation:

Step 1: Define

Identify variables

F = 755 N

m = 15 kg

Step 2: Solve for a

Substitute in variables [Newton's 2nd Law of Motion]: 755 N = (15 kg)a
Isolate a: a = 151/3 m/s²

Topic: AP Physics 1 - Algebra Based

Unit: Forces

cluponka [151]2 years ago

3 0

Answer:

good question!

Explanation:

You might be interested in

A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew

Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

Where

L = Thickness

n = Index of refraction of each material

$\lambda =$ Wavelength

Our values are given as

$\Phi = 7(2\pi)$

$L=t$

$n_1 = 1.58$

$n_2 = 1$

$\lambda = 550nm$

Replacing our values at the previous equation we have

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

$7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))$

$t = \frac{7*550}{1.58-1}$

$t = 6637.931nm \approx 6.64\mu m$

Therefore the thickness of the mica is 6.64μm

3 0

3 years ago

A 1 900-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.00 m before coming into contact

Leno4ka [110]

Answer:

471392.4 N

Explanation:

From the question,

Just before contact with the beam,

mgh = Fd.................... Equation 1

Where m = mass of the beam, g = acceleration due to gravity, h = height. F = average Force on the beam, d = distance.

make f the subject of the equation

F = mgh/d................ Equation 2

Given: m = 1900 kg, h = 4 m, d = 15.8 = 0.158 m

Constant: g = 9.8 m/s²

Substitute into equation 2

F = 1900(4)(9.8)/0.158

F = 471392.4 N

6 0

3 years ago

Why is it harder to breathe on a

Law Incorporation [45]

I think it’s d but I’m not sure

6 0

3 years ago

Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight dow

bulgar [2K]

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

$F=\frac{\Delta p}{\Delta t}$

where

F is the force exerted

$\Delta p$ is the change in momentum

$\Delta t$ is the time interval

The change in momentum can be rewritten as

$\Delta p = m(v-u)$

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

$F=\frac{m(v-u)}{\Delta t}$

In this problem we have:

$\frac{m}{\Delta t}=0.030 kg/s$ is the mass rate

$u=-15 m/s$ is the initial velocity

$v=+15 m/s$ is the final velocity

Therefore, the force exerted by the hail on the roof is:

$F=(0.030)(+15-(-15))=0.9 N$

6 0

3 years ago

PLEASE HELP ASAP!! Which of the following diagrams represents a complete series circuit?

Iteru [2.4K]

your answer would be The one in the top right corner that looks a bit like this..

3 0

3 years ago