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kolbaska11 [484]
3 years ago
5

One isotope of a metallic element has the mass number 67 and 37 neutrons in the nucleus. The cation derived from the isotope has

28 electrons. Write the atomic symbol for this element.
Chemistry
2 answers:
Anuta_ua [19.1K]3 years ago
6 0
No. Of protons = mass no. - no. Of neutrons
No. Of protons = 67 - 37
= 30
No. Of electrons = 28

Zinc will have 30 protons and 28 electrons. So, it will have +2 charge

Symbol - Zn^+2
miv72 [106K]3 years ago
5 0

Answer:

Zinc: Zn

Explanation:

The mass number of element is 67

mass number = number of protons + number of neutrons

So number of protons = 67-37=30

Thus the atomic number of element is 30

the atom with atomic number 30 is zinc

On losing 2 electrons it will form dipositive ion which will have 28 electrons

The symbol of element is Zn

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0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t
alina1380 [7]

Answer:

M=6.03M

Explanation:

Hello,

In this case, since the molarity is computed by:

M=\frac{n_{solute}}{V_{solution}}

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L

Therefore, the molarity turns out:

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6 0
3 years ago
2.0L of hydrogen gas is mixed with 3.0L of nitrogen gas at STP in a rigid 5.0L vessel. A reaction occurs, producing ammonia gas
IrinaK [193]

Answer:

Moles NH₃: 0.0593

0.104 moles of N₂ remain

Final pressure: 0.163atm

Explanation:

The reaction of nitrogen with hydrogen to produce ammonia is:

N₂ + 3 H₂ → 2 NH₃

Using PV = nRT, moles of N₂ and H₂ are:

N₂: 1atmₓ3.0L / 0.082atmL/molKₓ273K = 0.134 moles of N₂

H₂: 1atmₓ2.0L / 0.082atmL/molKₓ273K = 0.089 moles of H₂

The complete reaction of N₂ requires:

0.134 moles of N₂ × (3 moles H₂ / 1 mole N₂) = <em>0.402 moles H₂</em>

That means limiting reactant is H₂. And moles of NH₃ produced are:

0.089 moles of H₂ × (2 moles NH₃ / 3 mole H₂) = <em>0.0593 moles NH₃</em>

Moles of N₂ remain are:

0.134 moles of N₂ - (0.089 moles of H₂ × (1 moles N₂ / 3 mole H₂)) = <em>0.104 moles of N₂</em>

And final pressure is:

P = nRT / V

P = (0.104mol + 0.0593mol)×0.082atmL/molK×273K / 5.0L

<em>P = 0.163atm</em>

7 0
3 years ago
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