1 plus 1 divisble times 900 to the power of 4

Ahat [919]

Answer:

4 minutes.

Step-by-step explanation:

There are three trains that Rachel has to take to go to her job. The total time is taken by her, on average, 1 hour and 20 minutes i.e. (60 + 20) = 80 minutes.

In his journey, she walks for 15 minutes and a train journey for about 53 minutes.

Then the total waiting time for the trains is (80 - 53 - 15) = 12 minutes.

Therefore, the average waiting time, in minutes, at each of the three train stations will be $\frac{12}{3} = 4$ minutes. (Answer)

8 0

3 years ago

At a basketball game, a team made 54 successful shots. They were a combination of 1- and 2-point shots. The team scored 93 po

Zepler [3.9K]

Answer:

iwillanswer

Genius

4.3K answers

14.6M people helped

17 one point shots and 39 two point shots were made

Solution:

Given that,

At a basketball game, a team made 56 successful shots

They were a combination of 1- and 2-point shots

Let "x" be the number of 1 point shots

Then, 56 - x is the number of two point shots

The team scored 95 points in all

Therefore,

1(number of 1 point shots) + 2(number of two point shots) = 95

x + 2(56 - x) = 95

x + 112 - 2x = 95

x = 112 - 95

x = 17

Then, number of two point shots = 56 - x = 56 - 17 = 39

Thus 17 one point shots and 39 two point shots were made

8 0

3 years ago

Help me find the answer <br>Tan 0 and Cot O

vesna_86 [32]

Answer:

Step-by-step explanation:

we can say the angle is also +45° going in the clock wise direction. so take Tan(45)= 1

Cot(45) = 1

b/c Tan(45) = Sin(45) /Cos(45) = ( $\sqrt{2}$ /2) / ( $\sqrt{2}$ /2) ofc that's just 1

b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1

3 0

3 years ago

Convert 3 miles into yards

miskamm [114]

Answer:

5,280

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers