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Goshia [24]
3 years ago
7

You can see a clock in a spaceship moving past you at 90 percent of the speed of light. according to you, how much time would pa

ss while the clock in the spaceship ticked through one minute?
Physics
1 answer:
Dafna11 [192]3 years ago
5 0
t = \gamma\tau, \textnormal{   where } \gamma \equiv \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}, \textnormal{   }\tau \textnormal{ is the proper time 60s} 
 \\ 
t =  \frac{60s}{\sqrt{1-0.9^2}} = 137.65s  \textnormal{ } (5 s.f.)
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C. Polarized in a vertical plane.

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3 years ago
This should be correct
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Show us a drawing, an equation, an expression, a statement ... something !

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3 years ago
19. A person pushes with 6.0 N for 4.0 seconds on a 2.0 kg object.
hram777 [196]

Answer:24NS

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3 years ago
Five properties of magnet​
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Answer:

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3 0
3 years ago
Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista
soldi70 [24.7K]

Answer:

v = 7793150 m/s

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

v = \frac{kQ}{r}

                 Where     k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }

and it is satisfy the superposition principle, thus

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}

v = 222.73v

The electrical potential at 10 cm from charge 1 is:

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}

v = 395.44 v

Since the work - energy theorem, we have:

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Therefore:

v = \sqrt{\frac{2q\Delta v}{m} }

v = 7793150 m/s

6 0
3 years ago
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