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Veseljchak [2.6K]
3 years ago
15

2. Calculate the slope of the line in your graph of the square of the period of the pendulum vs. length of the string .Galileo f

igured out the equation that describes the behavior of a pendulum. If you square both sides of the equation, you will find that the slope of the line is related to the acceleration due to gravity (g). Specifically, . Use your data to calculate g. How does it compare with the accepted value of ? Calculate the percent error and show your work.
Physics
1 answer:
Alla [95]3 years ago
4 0
The period is given by T=2 \pi  \sqrt{ \frac{l}{g} }
Squaring this gives
4  \pi ^{2}  \frac{l}{g}
Plotting this period as a function of length l gives
T=ml
where the slope, m, is
\frac{4 \pi ^{2} }{g}=4.0243
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Answer:

Volt

Explanation:

Voltage is what makes electric charges move. ... Voltage is also called, in certain circumstances, electromotive force (EMF). Voltage is an electrical potential difference, the difference in electric potential between two places. The unit for electrical potential difference, or voltage, is the volt.

The ohm is defined as an electrical resistance between two points of a conductor when a constant potential difference of one volt, applied to these points, produces in the conductor a current of one ampere, the conductor not being the seat of any electromotive force.

The coulomb (symbolized C) is the standard unit of electric charge in the International System of Units (SI). ... In terms of SI base units, the coulomb is the equivalent of one ampere-second. Conversely, an electric current of A represents 1 C of unit electric charge carriers flowing past a specific point in 1 s.

An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor. One ampere of current represents one coulomb of electrical charge (6.24 x 1018 charge carriers) moving past a specific point in one second.

8 0
3 years ago
You are traveling on an interstate highway at the posted speed limit of 70 mph when you see that the traffic in front of you has
vovikov84 [41]

Answer:8.75 s,

136.89 m

Explanation:

Given

Initial velocity=70 mph\approx 31.29 m/s

velocity after 5 s is 30 mph\approx 13.41 m/s

Therefore acceleration during these 5 s

a=\frac{v-u}{t}

a=\frac{13.41-31.29}{5}=-3.576 m/s^2

therefore time required to stop

v=u+at

here v=final velocity =0 m/s

initial velocity =31.29 m/s

0=31.29-3.576\times t

t=\frac{31.29}{3.576}=8.75 s

(b)total distance traveled before stoppage

v^2-u^2=2as

0^2-31.29^2=2\times (-3.576)\cdot s

s=136.89 m

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Montano1993 [528]

Answer: yes

Explanation:

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