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KengaRu [80]
3 years ago
5

A boy with a mouse is 80 kg stands on a scale in an ascending elevator with an acceleration of 3 m/s What is the resultant upwar

d force acting on the boy due to the motion of the elevator
Physics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

Upward force on the boy will be 1024 N      

Explanation:

We have given mass of the boy m = 80 kg

Acceleration due to gravity g=9.8m/sec^2

It is given that elevator is ascending with acceleration of 3m/sec^2

So net acceleration on the boy = 9.8+3 = 12.8 m/sec^2 ( As the car elevator is moving ascending )

So upward force on the boy will be equal to F = m(g+a)

So F=80\times 12.8=1024N

So upward force on the boy will be 1024 N

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A 72-kg skydiver is falling from 10000 feet. At an instant during the fall, the skydiver
MissTica

Answer:

Approximately 2.31\; \rm m \cdot s^{-2} (assuming that the acceleration due to gravity isg = 9.81\; \rm m \cdot s^{-2}.)

Explanation:

Assuming that g = 9.81\; \rm m \cdot s^{-2} the weight on this 72-kg skydiver would be W = m \cdot g = 72 \; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 706.32\; \rm N (points downwards.)

Air resistance is supposed to act in the opposite direction of the motion. Since this skydiver is moving downwards, the air resistance on the skydiver would point upwards.

Therefore, the net force on this skydiver should be the difference between the weight and the air resistance on the skydiver:

\begin{aligned}F(\text{net force}) &= W - F(\text{air resistance})\\ &= 706.32\; \rm N - 540\; \rm N =166.32\; \rm N \end{aligned}.

Apply Newton's Second Law of motion to find the acceleration of this skydiver:

\begin{aligned}a &= \frac{F(\text{net force})}{m} \\ &= \frac{166.32\; \rm N}{72\; \rm kg} = 2.31\; \rm m \cdot s^{-2} \end{aligned}.

5 0
3 years ago
If a 100-N net force acts on a 50-kg car, what will the acceleration of the car be?
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Newton's 2nd law of motion: 

                             Force = (mass) x (acceleration)

Divide each side by (mass):     

                             Acceleration = (force) / (mass)

                                               =  (100 N) / (50 kg)

                                               =  2 m/s²  


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