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2 years ago

How would you use the index of refraction of salt water to find the concentration of a salt solution?

1 answer:

3 0

As the salt solution increases its salinity, its refractive index also increases, with decreasing temperature. Through this relationship, the refractive index of salt solution at a constant temperature can be used to determine the concentration of the said solution.

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A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the

Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height, is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

3 0

2 years ago

Read 2 more answers

Suppose your car is on a 5% grade, meaning that for every 100 m you travel along the road you raise or lower only 5 m in elevati

kvv77 [185]

Answer:

734.215N

Explanation:

First we calculate the angle that corresponds to a 5% slope using the Tan-1 function

$\beta = tan-1(5%)=2.86$

then we use the component that corresponds to the direction parallel to the road, additionally we must multiply by the gravity value to find the weight(g=9.81m/s^2)

Wx=M*g*sen(2.86)=1500kg*9.81*sen(2.86)=734.215N

8 0

3 years ago

Read 2 more answers

If you push a crate across a factory floor at constant speed in a constant direction, what is the magnitude of the force of fric

poizon [28]

Answer:

The magnitude of the force of friction equals the magnitude of my push

Explanation:

Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.

Let F = push and f = frictional force and f' = net force

F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0

So, F - f = 0

Thus, F = f

So, the magnitude of the force of friction equals the magnitude of my push.

3 0

2 years ago

the distance between two points P and Q is 120 m a object goes from point P to q and then returned to P in 1 minute 40 second wh

Naily [24]

Answer:

using a formula

average velocity=total displacement/total time

average velocity=120/1minute40sec

1minute=60sec

60sec+40sec=120sec

average velocity=120m/120sec

average velocity=1m/sec

3 0

2 years ago

Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards

Stels [109]

1. Tangential velocity:

e) the instantaneous velocity of a body moving in a circular path.

2. Parabolic pathway

c. a curved path followed by projectiles

3. Projectile

d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.

4. Centripetal acceleration

a) acceleration towards the center caused by the centripetal force

5. Centripetal force

b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center

4 0

2 years ago