Ask question

Ask question

All categories

2 years ago

10

Which of the following have the same density. number 26

1 answer:

marusya05 [52]2 years ago

8 0

1 cubic cm is the same as 1 mL, so the answer would be C.

You might be interested in

5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there

Jobisdone [24]

Answer:

the fractional loss per pass =0.053

the decay time of the cavity =11 ns

Explanation:

laser is an acronym for Light Amplification by Stimulated Emission of Radiation and it has lot of military applications : basically ranging from target acquisition, fire control, and training. It is also being used in LIDAR communications, radar systems , laser guided landing systems, laser pointers, holography, photography, guidance systems, scanning machines, metal working, and medicine.

the fractional loss per pass= $\alpha l - ln(R_1R_2)^ \frac {1}{2}$

but no excited state absorption, therefore $\alpha$ is 0

$= - ln(R_1R_2)^ \frac {1}{2}\\\\=- ln(0.999* 0.9)^ \frac {1}{2}$

=0.053

b) the decay time of the cavity:

$T_c = \frac{nd}{cl_f}=\frac{1,76 * 10 *10^-2}{3 *10^8 *0.53}$

=1.1 *10^-8 seconds

=11 ns

3 0

3 years ago

Heat is extracted from a certain quantity of steam at

vodomira [7]

Answer: $v=2452.91 m/s$

Explanation:

Given

initially steam is at $100^{\circ}C$ and converted to $0^{\circ} C$ ice

Let m be the mass of steam

latent heat of fusion and vaporization for water is

$L_f=3.33\times 10^5 J/kg$

$L_v=2.26\times 10^6 J/kg$

Heat required to convert steam in to water at $100^{\circ}C$

$Q_1=m\times L_v=m\cdot 2.26\times 10^6 J$

Heat required to lower water temperature to $0^{\circ}C$

$Q_2=m\times c\times \Delta T$

$Q_2=m\times 4.184\times (100)$

$Q_2=4.184m\times 10^5 J$

Heat required to convert $0^{\circ}C$ water to ice at $0^{\circ}C$ is

$Q_3=m\times L_f$

$Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J$

$Q=Q_1+Q_2+Q_3$

$Q=(2.26+0.4184+0.33)m\times 10^6 J$

$Q=3.0084m\times 10^6 J$

So this energy is equal to kinetic energy of bullet of mass m moving with velocity v

$Q=\frac{1}{2}mv^2$

$3.0084m\times 10^6=\frac{1}{2}mv^2$

$v^2=3.0084\times 2\times 10^6$

$v=2.452\times 10^3 m/s$

$v=2452.91 m/s$

5 0

3 years ago

You and your friend Peter are putting new shingles on a roof pitched at 21∘. You're sitting on the very top of the roof when Pet

Marat540 [252]

Answer:

3.69 m/s

Explanation:

Forces :

mgsin Θ - mumgcosΘ = ma

g x sinΘ - mu x g x cosΘ = a

9.8 x sin 21 - 0.53 x 9.8 x cos 21 = a

a = -1.337 m/s²

so you have final velocity = 0 m/s

initial velocity = ? m/s

Given d = 5.1 m

By kinematics

vf² = vo² + 2ad

0 = vo² + 2 x -1.337*5.1

vo = 3.69 m/s

8 0

3 years ago

A total of 875 J of work was done when a force of 175 N was exerted on a box to move it. How far was the box moved

Vladimir [108]

Work = Force times Distance
W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
d = 750/125
d = 6

The box moved a distance of 6 meters.

3 0

1 year ago

8 colors according to their alphabetical order

damaskus [11]

Answer:

8 colors in alphabetical order are

Black

blue

brown

Green

Orange

Pink

Purple

Yellow

Explanation:

6 0

2 years ago