Which of the following have the same density. number 26

A student is told to use 20.0 g of sodium chloride to make an aqueous solution that has a concentration of 10.0 g/L (grams of so

Stells [14]

Answer:

she should add solute to the solvent

Explanation:

Given data :

Mass of the sodium chloride, = 20.0 g

Concentration of the solution = 10 g/L

Volume of 20.0 g of sodium chloride = 7.50 mL

Now, from the concentration, we can conclude that for 10 g of sodium chloride volume of the solution is 1 L

thus, for 20 g of sodium chloride volume of the solution is 2 L or 2000 mL

also,

Volume of solution = Volume of solute(sodium chloride) + volume of solvent (water)

thus,

2000 mL = 7.5 mL + volume of solvent (water)

or

volume of water = (2000 - 7.5) mL

or

volume of water = 1992.5 mL

or

volume of water = 199.25 L ≈ 199 L

6 0

3 years ago

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Which of the following expressions is equivalent to the expression 2(x + 5)? x + 7 x + 10 2x + 5 2x + 10

bezimeni [28]

Answer:

d) 2x+10

Explanation:

$2(x+5)\\=2x+10$

6 0

4 years ago

You are one of the forensic anthropologist working on the Romanov Family investigation. You and your team are trying to determin

yawa3891 [41]

Answer:

Femur

Explanation:

The bone to forensically analyze in order to create a height profile of the victims would the femur.

The approximate height of a human can best be estimated by measuring the length of the bone that runs from the hip to the knee, otherwise known as the femur.

For the males, the length of the femur in centimeters is multiplied by 2.32 followed by the addition of 65.53 in order to arrive at the approximate height of the individual. For the females, on the other hand, the length of the femur in centimeters is multiplied by 2.47 followed by the addition of 54.1.

7 0

3 years ago

It is raining outside, so a student lifts their textbook vertically 1.2 meters above

Nadusha1986 [10]

Answer:

Work done is 50.4J.

Explanation:

The work $W$ done by the student in lifting the book 1.2 meters vertically is

$W =42N*1.2m$

$\boxed{W = 50.4J}$

When the student begins to walk horizontally, the net force on the book is zero (gravity is pulling it down, the student is lifting it up). Thus, although the student is displacing the book horizontally, but because no force is exerted on it, the work done is zero.

3 0

4 years ago

A car, starting from the origin, travels

sweet [91]

Answer:

The net displacement of the car is 3 km West

Explanation:

Please see the attached drawing to understand the car's trajectory: First in the East direction for 4 km (indicated by the green arrow that starts at the origin (zero), and stops at position 4 on the right (East).

Then from that position, it moves back towards the West going over its initial path, it goes through the origin and continues for 3 more km completing a moving to the West a total of 7 km. This is indicated in the drawing with an orange trace that end in position 3 to the left (West) of zero.

So, its NET displacement considered from the point of departure (origin at zero) to the final point where the trip ended, is 3 km to the west.

8 0

3 years ago

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