The work done by the centripetal force during om complete revolution is 401.92 J.
<h3>What is centripetal force?</h3>
Centripetal force is a force that acts on a body undergoing a circular motion and is directed towards the center of the circle in which the body is moving.
To Calculate the work done by the centripetal force during one complete revolution, we use the formula below.
Formula:
- W = (mv²/r)2πr
- W = 2πmv²................... Equation 1
Where:
- W = Work done by the centripetal force
- m = mass of the ball
- v = velocity of the ball
- π = pie
From the question,
Given:
- m = 16 kg
- v = 2 m/s
- π = 3.14
Substitute these values into equation 1
Hence, The work done by the centripetal force during om complete revolution is 401.92 J.
Learn more about centripetal force here: brainly.com/question/20905151
The answer should be 5 it’s easy
Explanation:
It is given that,
Mass of the tackler, m₁ = 120 kg
Velocity of tackler, u₁ = 3 m/s
Mass, m₂ = 91 kg
Velocity, u₂ = -7.5 m/s
We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,
v = -1.5 m/s
Hence, their mutual velocity after the collision is 1.5 m/s and it is moving in the same direction as the halfback was moving initially. Hence, this is the required solution.
Answer:
Gravitational force mg' =(49)mg=49×63=28N.
Explanation:
What is the gravitational force on it due to the Earth , at a height equal to half the radius of the Earth ? (Given that the radius of Earth = 6400 km). Gravitational force mg ( This is not the real explanation)
