What structural feature of lecithin allows it to behave like an emulsifying agent?

1 answer:

6 0

Lecithin is an emulsifier agent that's composed of 5 smaller molecules: phosphoric acid, choline, glycerol( is the backbone), and two fatty acids.

The fatty acids, which are hydrophobic (afraid of water), makes this substance more similiar to fats and represent the non-polar part of the lecithin.
The phosphate group is the polar portion of the molecule and it's the negatively charged. The choline is positively charged, which readily dissolve in water<span>.

</span><span>Lecithin is a good emulsifier because of these structural features. the hydrophobic contacts with the oil, while the hydrophilic end contacts with the water.</span>

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Answer:

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Explanation:

Example:

Assume an electron transition from n = 5 to n = 2.

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How many particles of CuCr2O7 are present in a 64.5 gram sample?

kow [346]

<h3>Answer:</h3>

1.39 × 10²³ particles CuCr₂O₇

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 64.5 g CuCr₂O₇

[Solve] particles CuCr₂O₇

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of Cr - 52.00 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CuCr₂O₇ - 63.55 + 2(52.00) + 7(16.00) = 279.55 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 64.5 \ g \ CuCr_2O_7(\frac{1 \ mol \ CuCr_2O_7}{279.55 \ g \ CuCr_2O_7})(\frac{6.022 \cdot 10^{23} \ particles \ CuCr_2O_7}{1 \ mol \ CuCr_2O_7})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 1.38944 \cdot 10^{23} \ particles \ CuCr_2O_7$