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STALIN [3.7K]
3 years ago
13

What do the symbols in the parentheses indicate

Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Answer:

(C) the physical state of each reactant and product

Explanation:

Hope this helps

You might be interested in
Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

Learn more about the density here:

brainly.com/question/952755

#SPJ1

8 0
2 years ago
Mass = 200.0 g volume = 100.0cm3 What is the density?
Marianna [84]
The density of an object is defined as its mass divided by its volume. Mathematically, density = Mass / Volume. The unit of density is kilogram per cubic meter, kg / m^3 or g /cm^3.
For the question given above: the 
Mass = 200.0 g
Volume = 100.0 cm^3
Therefore, Density = Mass / Volume = 200 / 100  = 2
Thus,  the density of the object is 2 g /cm^3.
3 0
3 years ago
List two of the kingdoms found in the Eukarya domain
IrinaK [193]
Animalia and Plantae

Hope that helps
6 0
3 years ago
A 143.1 g sample of a compound contains 53.4 g of carbon, 16.9 g of hydrogen, 43 g of nitrogen, and some amount of oxygen. what
nika2105 [10]
I'm fairly sure this is it 20.82%
6 0
3 years ago
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Which product is made up of fatty acids that are derived from alkenes?
Aleksandr-060686 [28]

The answer is A) Margarine ;)

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3 years ago
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