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stealth61 [152]
3 years ago
7

which of the following antibiotic products may cause a cross sensitivity reaction in patients who are allergic to penicillin?​

Chemistry
2 answers:
Amiraneli [1.4K]3 years ago
5 0

Answer:

The beta-lactam ring, the thiazolidine/dihydrothiazine ring and the side-chains are all potentially immunogenic. Cross-reactivity between penicillin and third-generation cephalosporins occurs in 2% to 3% of penicillin-allergic patients.

This is one of the answers.

The second is

The cephalosporin medications that are likely to cross-react after penicillin allergies have been established and include: Cephalexin. Cefadroxil. Ceflaclor.

Dominik [7]3 years ago
3 0

Answer:

Can you provide the options pls

Explanation:

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How does the use of hydroelectric energy compare to the use of coal?
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4 0
4 years ago
How many grams of oxygen can be obtained from 250. grams of KCIO3?
guapka [62]

Answer:

Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.

Explanation:

3 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
Si Units Worksheet. Use si units to complete
Keith_Richards [23]

\\ \bull\tt\dashrightarrow 2000m=2km

\\ \bull\tt\dashrightarrow 9000mL=9L

\\ \bull\tt\dashrightarrow 6L=6000mL

\\ \bull\tt\dashrightarrow 6cm=60mm

\\ \bull\tt\dashrightarrow 1000m=1km

\\ \bull\tt\dashrightarrow 50mm=5cm

\\ \bull\tt\dashrightarrow 4L=4000mL

\\ \bull\tt\dashrightarrow 10000g=10kg

\\ \bull\tt\dashrightarrow 10000m=10km

\\ \bull\tt\dashrightarrow 4000g=4kg

\\ \bull\tt\dashrightarrow 9km=9000m

\\ \bull\tt\dashrightarrow 3kg=3000g

\\ \bull\tt\dashrightarrow 90mm=9cm

\\ \bull\tt\dashrightarrow 4km=4000m

\\ \bull\tt\dashrightarrow 2000g=2kg

\\ \bull\tt\dashrightarrow 400cm=4m

\\ \bull\tt\dashrightarrow 3km=3000m

\\ \bull\tt\dashrightarrow 2cm=20mm

\\ \bull\tt\dashrightarrow 9000g=9kg

8 0
3 years ago
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