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stealth61 [152]
3 years ago
7

which of the following antibiotic products may cause a cross sensitivity reaction in patients who are allergic to penicillin?​

Chemistry
2 answers:
Amiraneli [1.4K]3 years ago
5 0

Answer:

The beta-lactam ring, the thiazolidine/dihydrothiazine ring and the side-chains are all potentially immunogenic. Cross-reactivity between penicillin and third-generation cephalosporins occurs in 2% to 3% of penicillin-allergic patients.

This is one of the answers.

The second is

The cephalosporin medications that are likely to cross-react after penicillin allergies have been established and include: Cephalexin. Cefadroxil. Ceflaclor.

Dominik [7]3 years ago
3 0

Answer:

Can you provide the options pls

Explanation:

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Gas law problem: A gas has a volume of 800 mL at -25℃ and 600 kPa. What would the volume of the gas be at 227℃ and 1000 kPa?
Sati [7]
<h3><u>Answer;</u></h3>

= 930.23 mL

<h3><u>Explanation</u>;</h3>

Using the combined gas law;

P1V1/T1 = P2V2/T2

Where; P1 = 600 kPa, V1 = 800 mL, and T1 = -25 +273 = 258 K, and

V2= ?, P2 = 1000 kPa, and T2 = 227 +273 = 500 K

Thus;

V2 = P1V1T2/T1P2

     = (600 ×800 ×500) / (258 × 1000)

     = 930.23 mL

5 0
3 years ago
Which bond is least polar <br> N-O<br><br> S-O<br><br> H-O<br><br> C-O
Sphinxa [80]

Answer:

Her Eid per Ruth Jααte Hαin wo Humse,

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ہر عید پر روٹھ جاتے ہیں وہ ہم سے

اب بتاؤ ہم عید منائے یا ان کو

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8 0
3 years ago
In a unimolecular reaction with twice as much starting material as product at equilibrium, what is the value of Keq? Is ΔG o pos
lubasha [3.4K]

Answer : The value of K_{eq} is, 0.5 and \Delta G= positive.

Explanation :

The unimolecular reaction is:

A\rightarrow B

In unimolecular reaction, the starting material is 2 times to the product.

A=2B      .........(1)

As we know that:

K_{eq}=\frac{B}{A}     ...........(2)

Now substitute equation 1 in 2, we get:

K_{eq}=\frac{\frac{A}{2}}{A}

K_{eq}=0.5

Now we have to calculate the value of \Delta G^o at 298 K.

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

K_{eq} = equilibrium constant = 0.5

Now put all the given values on the above formula, we get:

\Delta G^o=-(8.314J/mol.K)\times (298K)\ln (0.5)

\Delta G^o=1717.32J/mol

Thus, the value of \Delta G^o at 298 K is, 1717.32 J/mol

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus, the \Delta G= +ve. So, the reaction is non spontaneous.

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3 years ago
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ddd [48]
I think it would be c
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3 years ago
What is The charge of PbI2
4vir4ik [10]

Answer:

Lead iodide (II) is an inorganic compound, lead salt and hydrogen acid, with the PbI2 formula.

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3 years ago
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