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topjm [15]
2 years ago
6

How many moles are in 11.5 L of a gas at STP?

Chemistry
1 answer:
garik1379 [7]2 years ago
6 0

Answer:

0.51mole

Explanation:

Given parameters:

Volume of gas  = 11.5L

Unknown:

Number of moles = ?

Solution:

Since the gas is at STP,

     Number of moles  = \frac{volume of the gas }{22.4}  

    Insert parameters:

 Number of moles  = \frac{11.5}{22.4}   = 0.51mole

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Naturally occurring zirconium exists are five isotopes. axe with a mass of 89.905 u(51.45%); Zr with a mass of 90.906 u (11.22%)
Anton [14]
Isotope 1: 89.905 * 51.45 = 4625.61225 / 100 = 46.2561225
Isotope 2: 90.906 * 11.22 = 1019.96532 / 100 = 10.1996532
Isotope 3: 91.905 * 17.15 = 1576.17175 / 100 = 15.7617075
Isotope 4: 93.906 * 17.38 = 1632.08628 / 100 = 16.3208628
Isotope 5: 95.908 * 2.08 = 268.5424 / 100 = 2.685424

46.2561225 + 10.1996532 +  15.7617075 + 16.3208628 + 2.685424 = 91.22377
actual mass Zr = about 91.22
8 0
3 years ago
How does the size change when an atom forms a cation and when an atom forms an anion?
mario62 [17]
<span>A cation is an atom that loses a valence electron. When a valence electron is released there is one electron less to create a repulsive force. The loss of a repulsive force will allow the atom to pull tighter together. An anion would therefore be larger in size due to increased repulsion of the valence electrons.</span>
8 0
3 years ago
So guess what I did!!
Lapatulllka [165]

Answer:

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7 0
3 years ago
How do you figure out the final temperature or the initial temperature in calorimetry.
Zolol [24]
Add the change in temperature to your substance's original temperature to find its final heat. For example, if your water was initially at 24 degrees Celsius, its final temperature would be: 24 + 6, or 30 degrees Celsius.
4 0
2 years ago
Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.
Serga [27]
I suspect that the pressure of this change is constant therefore

The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial   Change

Initially we have 2L at 20 degress what temperature will be at 1L.

2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.

Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
3 0
3 years ago
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