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2 years ago

A positive charge is placed in an electric field that points west. What direction

Physics

1 answer:

Leno4ka [110]2 years ago

5 0

Answer:

South

Explanation:

If the electric field points South, then a positive particle is going to be repelled, because field lines point away from the positive end of a magnet. so the positive charge is going to go south. Please mark brainliest!

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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.245 T. If the kinetic energy of the electr

Amiraneli [1.4K]

Answer

Given,

Magnetic field, B = 0.245 T

KE of the electron = 2.90 x 10⁻¹⁹ J

Speed of electron = ?

$KE = \dfrac{mv^2}{2}$

$v=\sqrt{\dfrac{2(KE)}{m}}$

$v=\sqrt{\dfrac{2\times 2.90\times 10^{-19}}{9.11\times 10^{-31}}}$

v = 7.97 x 10⁵ m/s

radius of the circular path

so,

$\dfrac{mv^2}{r}=evB$

$r=\dfrac{mv}{eB}$

$r=\dfrac{9.11\times 10^{-31}\times 7.97 \times 10^5}{1.6\times 10^{-19}\times 0.245}$

r = 1.85 x 10⁻⁵ m

8 0

3 years ago

A 50-loop circular coil has a radius of 3 cm. It is oriented so that the field lines of a magnetic field are perpendicular to th

nikitadnepr [17]

Answer:

-17.8 V

Explanation:

The induced emf in a coil is given as:

$E = \frac{-NdB\pi r^2}{dt}$

where N = number of loops

dB = change in magnetic field

r = radius of coil

dt = elapsed time

From the question:

N = 50

dB = final magnetic field - initial magnetic field

dB = 0.35 - 0.10 = 0.25 T

r = 3 cm

dt = 2 ms = 0.002 secs

Therefore, the induced emf is:

$E = \frac{-50 * 0.25 * \pi * 0.03^2}{0.002} \\E = -17.8 V$

Note: The negative sign implies that the EMf acts in an opposite direction to the change in magnetic flux.

6 0

3 years ago

How can we get a clue as to the temperature of a star

Juli2301 [7.4K]

The colour of the star and the brightness.

8 0

3 years ago

A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 k

tangare [24]

Answer:The velocity of the object will be 5 $\sqrt7$ m/s or 13.23m/s

Explanation:

force exerted by the object= 30N

distance displayed by the object by the action of force=6.0m

mass of object=10kg

velocity gained by the object=?

$\frac{1}{2}mv^{2}= forcexdisplacement\\\frac{1}{2}10v^{2} = 30x6\\ 5v^{2}=180\\ v^{2}= 180-5\\ v^{2} =175\\v=\sqrt{175} \\v=5\sqrt{7} or 13.23$

6 0

2 years ago

A(n) 71.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 70.2 m away from the shuttle

denpristay [2]

Answer:

10.347 minutes.

Explanation:

According to F = ma, she exerts force on camera of the magnitude

F = 0.67Kg*12m/ $s^{2}$ = 8.04N, assuming it took her one second to accelerate camera to 12m/s, then by newtons third law, which says every action has equal and opposite reaction , the camera exerts the same amount of force on the astronaut which gives her acceleration of a = $\frac{8.04N}{70.2Kg} = 0.1130801680m/s^2$ .

and velocity of V = 0.1130801680m/s.

at this velocity , the astronaut has to cover the distance of 70.2 meters, it will take her 620.7985075s = 10.347 min to get to the shuttle (using S = vt).

4 0

3 years ago