The oxidation number of an element is the number of electrons that are gained or lost by the element to form a chemical bond.
the net oxidation number of the ion is its charge.
compound (NH₄)₂Cr₂O₇ is made of cation - NH₄⁺ and anion - Cr₂O₇²⁻
oxidation number of ion - -2
(oxidation number of Cr x 2 Cr atoms) +(oxidation number of O x 7 O atoms )= -2
oxidation number of Cr = y
oxidation number of O = -2
(y x 2) + (-2 x 7) = -2
2y - 14 = -2
2y = 12
y = + 6
therefore oxidation number of Cr is +6
Looks correct but the second to last I would of put abiotic and biotic factors but I don’t know what’s right for you
Answer:
4.858 g
Explanation:
Start with the formula
density = 
density = 1.98 g/mL
volume = 2.45 mL
mass = ??
rearrange the formula to solve for mass
(density) x (volume) = mass
Add in the substitutes and solve for mass
1.98 g/mL x 2.45 mL = 4.858 g
Answer:
Hello
please make sure that there is any group which is join with alkane
Answer:
The Chemical formula of sodium is Na.
The Chemical formula of oxide is O.
Explanation:
Therefore we know that the term 'valency' is called as the combining capacity of an atom of an element.
So by taking the valency of Sodium and Oxide, we get
Sodium with valency '1' and Oxide with valency '2'.
Na O
1 2
When you cross over you get 'Na2O' as the formula for sodium oxide.
Hope this is helpful for you!
Don't forget to rate or give brainliest answer.!!
TY.
