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serg [7]
3 years ago
5

What happens to the power of an electric circuit if the resistance is decreased? Explain your answer.

Physics
1 answer:
atroni [7]3 years ago
3 0
If you lower the resistance the current speeds up and if the current gets to fast the wire with ignite with fire <span />
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What is the connection between change in momentum and impulse
Katena32 [7]
The change in momentum of an object equals the impulse applied to it
6 0
3 years ago
According to​ Newton's Law of​ Cooling, if a body with temperature Upper T 1 is placed in surroundings with temperature Upper T
lesantik [10]

Answer:

27.22 F.

Explanation:

T ( t ) = T₀ + ( T₁ - T₀)e^{-kt}

T ( t ) = 41 ,  T₀ = 0 , T₁ = 140 , t = 15

Put these values in the equation above

41 = ( 140 - 0 ) e^{-15k}

41/140 = e ^{-15k}

(41/140)^{1/3} = e ^{-5k}

Let after 20 minutes temperature becomes T

T = 0 + 140 e^{-k20}

T / 41 = e^{-5k }

= (41/140)^{1/3}

T = 41 X  (41/140)^{1/3}

= 27.22 F.

7 0
4 years ago
Which of these is a scalar quantity?
USPshnik [31]

Answer:

It would be C because quantity means numbers

6 0
3 years ago
Read 2 more answers
A uniform thin circular ring rolls without slipping down an incline making an angle θ with the horizontal. What is its accelerat
Mariana [72]

Answer:a=\frac{g\sin \theta }{2}

Explanation:

Given

inclination is \theta

let M be the mass and r be the radius of uniform circular ring

Moment of Inertia of ring I=mr^2

Friction will Provide the Torque to ring

f_r\times r=I\times \alpha

f_r\times r=mr^2\times \alpha

in pure Rolling a=\alpha r

\alpha =\frac{a}{r}

f_r=ma

Form FBD mg\sin \theta -f_r=ma

mg\sin \theta =ma+ma

2ma=mg\sin \theta

a=\frac{g\sin \theta }{2}

6 0
3 years ago
A 1,160 kg satellite orbits Earth with a tangential speed of 7,446 m/s. If the satellite experiences a centripetal force of 8,95
Juli2301 [7.4K]

Answer:

8.02×10⁵ m

Explanation:

Equation for centripetal force:

F = mv²/r

Solving for r:

r = mv²/F

Given:

F = 8955 N

m = 1160 kg

v = 7446 m/s

r = (1160 kg) (7446 m/s)² / 8955 N

r = 7.182×10⁶ m

The height above the surface is:

h = 7.182×10⁶ m − 6.38×10⁶ m

h = 0.802×10⁶ m

h = 8.02×10⁵ m

4 0
4 years ago
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